RRB NTPC CBT 2 Level 5 June-12-2022 Shift 1 Exam Previous Question Paper with Solutions

66) The area of a rectangle is 453.6 m². If its length is 27 m, then what is the perimeter of the rectangle?

A) 86.6 m
B) 87.6 m
C) 85.4 m
D) 89.8 m

View Answer

B) 87.6 m

Explanation:We are given:
* Area of the rectangle = 453.6 m²
* Length = 27 m
—
Step 1: Find the breadth
$\text{Area} = \text{Length} × \text{Breadth} ⇒ 453.6 = 27 × \text{Breadth} ⇒ \text{Breadth} = \frac{453.6}{27} = 16.8 \ \text{m}$
—
Step 2: Find the Perimeter
$\text{Perimeter} = 2 × (\text{Length} + \text{Breadth}) = 2 × (27 + 16.8) = 2 × 43.8 = \boxed{87.6 \ \text{m}}$
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✅ Final Answer: Option 2: 87.6 m ✅
Want a tip on how to quickly estimate dimensions from area and perimeter?

67) Ramdin started from his office and walked 15 km in the south direction and reached the bus stop, and then turned to his left and walked 8 km straight on the road. From there, he turned to his left, walked 15 km and reached the Central Library. After this, he turned to his left again and walked 4 km to reach his hostel. How far and in which direction is the hostel with respect to his office?

A) 12 km towards North
B) 7 km towards South
C) 4 km towards West
D) 4 km towards East

View Answer

D) 4 km towards East

Explanation:Let’s trace Ramdin’s path step by step:
—
Step-by-step Movement:
⇒1. Starts at Office
Walks 15 km South → Reaches Bus Stop
⇒2. Turns left → Faces East
Walks 8 km → Reaches some point
⇒3. Turns left again → Faces North
Walks 15 km → Reaches Central Library
⇒4. Turns left → Faces West
Walks 4 km → Reaches Hostel
—
Now, calculate final position:
* Vertical movement:
* 15 km South, then 15 km North → Net vertical = 0 km
* Horizontal movement:
* 8 km East, then 4 km West → Net horizontal = 4 km East
So, the hostel is 4 km East of the starting point (Office).
—
✅ Final Answer: Option 4: 4 km towards East ✅
Want a quick diagram method for direction problems like this?

68) Find the product of the greatest among the numbers 0.82, 0.802, 0.85, 0.085 with the smallest among the numbers 0.3,0.03, 0.203, 2.03

A) 0.246
B) 0.0255
C) 0.0225
D) 0.2406

View Answer

B) 0.0255

Explanation:We are asked to:
Find the product of:
* The greatest number among:
0.82, 0.802, 0.85, 0.085
* The smallest number among:
0.3, 0.03, 0.203, 2.03
—
Step 1: Identify the greatest number in the first group:
Compare:
* 0.82
* 0.802
* 0.85 ✅
* 0.085
✅ Greatest = 0.85
—
Step 2: Identify the smallest number in the second group:
Compare:
* 0.3
* 0.03 ✅
* 0.203
* 2.03
✅ Smallest = 0.03
—
Step 3: Multiply the two:
0.85 × 0.03 = 0.0255
—
✅ Final Answer: Option: 0.0255 ✅
Need a quick decimal multiplication trick?

69) Which of the following sites of Indus Valley Civilization is located in Punjab (India)?

A) Banawali
B) Balu
C) Kot Diji
D) Ropar

View Answer

D) Ropar

70) The amount payable on maturity of a certain sum which is invested for 5 years at a certain rate per cent p. a. is ₹9,800 and the amount payable on the same sum invested for 10 years at the same rate is ₹12,600. If simple interest is offered in both cases, the rate of interest p. a. is:

A) 10%
B) 7.8%
C) 8.5%
D) 8%

View Answer

D) 8%

Explanation:We are given:
* Amount after 5 years = ₹9,800
* Amount after 10 years = ₹12,600
* Interest is Simple Interest
* Need to find the rate of interest per annum
—
Step 1: Find interest for 5 years
Interest for 10 years = ₹12,600 – P
Interest for 5 years = ₹9,800 – P
Now subtract the two equations:
(12,600 – P) – (9,800 – P) = 2,800
So, Interest for 5 years = ₹2,800
→ Therefore, Simple Interest per year = ₹2,800 / 5 = ₹560
—
Step 2: Find Principal (P)
From 5-year amount: P + 2,800 = 9,800 ⇒ P = 7,000
—
Step 3: Use SI formula to find Rate
$\text{SI} = \frac{P × R × T}{100} ⇒ 2,800 = \frac{7000 × R × 5}{100}$
$2800 = 350R ⇒ R = \frac{2800}{350} = \boxed{8\%}$
—
✅ Final Answer: Option: 8% ✅

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