RRB NTPC CBT 2 Level 5 June-12-2022 Shift 1 Exam Previous Question Paper with Solutions

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76) Sunita won $\frac35$ of the marbles that were there in the beginning of the game. Ravi won $\frac23$ of the remaining marbles while Sunny won the remaining 60 marbles. How many marbles did Sunita win?

A) 240
B) 285
C) 270
D) 255

View Answer

C) 270

Explanation:Let the total number of marbles at the beginning = x
—
Step 1: Sunita won
$\frac{3}{5} × x = \frac{3x}{5}$ marbles
Remaining marbles = $x - \frac{3x}{5} = \frac{2x}{5}$
—
Step 2: Ravi won
$\frac{2}{3} × \frac{2x}{5} = \frac{4x}{15}$ marbles
Remaining marbles (won by Sunny) = $\frac{2x}{5} - \frac{4x}{15} = \frac{6x - 4x}{15} = \frac{2x}{15}$
—
Step 3: Sunny won 60 marbles
So, $\frac{2x}{15} = 60 ⇒ x = \frac{60 × 15}{2} = 450$
—
Step 4: Sunita won
$\frac{3}{5} × 450 = \boxed{270}$
—
✅ Correct Answer: 270

77) BYTEW is related to YWTEB following a certain logic. Following the same logic, AMFQC is related to QMFCA. Which of the following is TILDW related to following the same logic?

A) LTIWD
B) WTLID
C) WILDT
D) WLITD

View Answer

B) WTLID

Explanation:We are given a pattern:
BYTEW → YWTEB
Let’s analyze this transformation.
—
Step-by-step on BYTEW → YWTEB:
Original: B Y T E W
Transformed: Y W T E B
So:
* 1st → 5th (B → B)
* 2nd → 1st (Y → Y)
* 3rd → 3rd (T → T)
* 4th → 4th (E → E)
* 5th → 2nd (W → W)
Pattern:
New positions: 2, 5, 3, 4, 1
So BYTEW → positions rearranged as:
2nd, 5th, 3rd, 4th, 1st] Now apply the same logic to:
T I L D W
Pick:
* 2nd → I
* 5th → W
* 3rd → L
* 4th → D
* 1st → T
So final word = IWLDT
Now check options for a match:
1. LTIWD
2. WTLID
3. WILDT ✅
4. WLITD
—
✅ Correct Answer: WILDT

78) Who among the following was a British reformer, a campaigner for women’s rights and a supporter of Indian nationalism?

A) Annie Besant
B) Josephine Butler
C) Florence Nightingale
D) William Wilberforce

View Answer

A) Annie Besant

79) Which of the following ports is located on the western coast of India?

A) Ennore
B) Haldia
C) Cochin
D) Paradip

View Answer

C) Cochin

80) A family spends ₹4,600, ₹5,600, ₹4,800, ₹3,800, and ₹6,000 on groceries in the first 5 months of a year. How much should the family spend in the 6th month to make the 6 months average spending of the family on groceries to ₹4,500?

A) ₹2,200
B) ₹3,650
C) ₹4,500
D) ₹3,500

View Answer

A) ₹2,200

Explanation:We are given:
* Spendings in first 5 months:
₹4,600, ₹5,600, ₹4,800, ₹3,800, ₹6,000
* Desired average over 6 months: ₹4,500
—
Step 1: Total required for 6 months
Average × 6 = ₹4,500 × 6 = ₹27,000
—
Step 2: Total spent in first 5 months
₹4,600 + ₹5,600 + ₹4,800 + ₹3,800 + ₹6,000 = ₹24,800
—
Step 3: Amount needed in 6th month
₹27,000 − ₹24,800 = ₹2,200
—
✅ Correct Answer: 1. ₹2,200

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