RRB NTPC CBT 2 Level 5 June-12-2022 Shift 1 Exam Previous Question Paper with Solutions

11) The surface area of a sphere is 61600 sq. cm. Find the volume of the sphere (in cu m).
[Use л= $\frac{22}7$ ]

A) $\frac{4.312}3$
B) 4.312
C) $\frac{43.12}3$
D) 43.12

View Answer

A) $\frac{4.312}3$

Explanation:Surface Area of a Sphere = 61,600 cm²
We need to find Volume in m³
Use: $\pi = \frac{22}{7}$
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✅ Shortcut Steps:
⇒1. Use the formula for surface area to find radius quickly:
$\text{Surface area} = 4\pi r^2\Rightarrow r^2 = \frac{\text{Surface area}}{4\pi}\Rightarrow r^2 = \frac{61600}{4 × \frac{22}{7}} = \frac{61600 × 7}{88} = 4900\Rightarrow r = \sqrt{4900} = 70 \text{ cm}$
⇒2. Convert radius to meters:
$r = 70 \text{ cm} = 0.7 \text{ m}$
—
⇒3. Plug into volume formula in meters:
$V = \frac{4}{3} \pi r^3 = \frac{4}{3} × \frac{22}{7} × (0.7)^3= \frac{88}{21} × 0.343 ≈ 4.312 \text{ m}^3$
—
✅ Final Answer: 4.312
—
Pro Tip (Shortcut Memory Aid):
If surface area is given, always go:
$r^2 = \frac{\text{Surface Area} × 7}{88} \Rightarrow r = \sqrt{\text{that result}} \Rightarrow$ Plug into volume with r³
Want a PDF cheat sheet for common formulas and shortcuts like this?

12) There are 3 badminton players in each stream -Commerce, Science and Arts. A, B and C are from Commerce. P, Q and R are from Science. J, K and L are from Arts. A team of 4 badminton players are to be sent for a tournament with following conditions:
(i) There must be at least one student from each stream.
(ii) P will not go with Q or R.
(iii) A and C will always go together.
(iv) K and L will always go together.
Which of the following combinations of players is a possible combination for the tournament?

A) A, C, P and J
B) A, Q, R and J
C) B.Q, J and K
D) B, P, R and J

View Answer

A) A, C, P and J

Explanation:Here’s a shortcut method to quickly solve the problem:
Key Conditions:
⇒1. At least one from each stream: Make sure the team has players from Commerce, Science, and Arts.
⇒2. P will not go with Q or R: Exclude combinations where P is with Q or R.
⇒3. A and C always go together: If A is in the team, C must also be in.
⇒4. K and L always go together: If K is in the team, L must also be in.
Step-by-Step Process:
⇒1. Option 1: A, C, P, J
Commerce: A, C ✓
Science: P ✓
Arts: J ✓
P is not with Q or R, and A and C are together ✓. Valid.
⇒2. Option 2: A, Q, R, J
Commerce: A ✓
Science: Q, R ✓
Arts: J ✓
A and C are together, so this is valid.
Valid.
⇒3. Option 3: B, Q, J, K
⇒Commerce: B ✓
Science: Q ✓
Arts: J ✓
But K is without L, so it violates condition (iv).
Not valid.
⇒4. Option 4: B, P, R, J
Commerce: B ✓
Science: P, R ✓
Arts: J ✓
P and R cannot go together, violating condition (ii).
Not valid.
Final Answer:
A, C, P, and J is valid.

13) Valley of the Kings – one of the most important archaeological sites in the world is located in__________

A) Egypt
B) Norway
C) Turkey
D) Thailand

View Answer

A) Egypt

14) The following question is based on the given words.
PLAN FORE RAMP RANG SAND
If in each word, the fourth letter is changed to the next letter in the English alphabetical order, how many letter clusters thus formed will have two vowels?

A) Two
B) Three
C) None
D) One

View Answer

A) Two

Explanation:Here’s a shortcut method to solve the problem quickly:
Steps:
⇒1. Identify the fourth letter of each word.
⇒2. Change the fourth letter to the next letter in the alphabet.
⇒3. Count the vowels in the new word.
⇒4. Look for words with exactly 2 vowels.
Apply the steps to the words:
⇒1. PLAN: Fourth letter is N → Change it to O → New word: PLAO (Vowels: A, O → 2 vowels)
⇒2. FORE: Fourth letter is E → Change it to F → New word: FORF (Vowels: O → 1 vowel)
⇒3. RAMP: Fourth letter is P → Change it to Q → New word: RAMQ (Vowels: A → 1 vowel)
⇒4. RANG: Fourth letter is G → Change it to H → New word: RANH (Vowels: A → 1 vowel)
⇒5. SAND: Fourth letter is D → Change it to E → New word: SANE (Vowels: A, E → 2 vowels)
Result:
Words with 2 vowels: PLAO and SANE.
Final Answer:
Option 1: Two

15) From the given options, which two numbers should be interchanged so that the value of Y becomes 29?
6×4-5+9÷3=Y

A) 5 and 3
B) 4 and 5
C) 6 and 9
D) 9 and 3

View Answer

B) 4 and 5

Explanation:Let’s solve this step by step.
Given equation:
$6 × 4 - 5 + \frac{9}{3} = Y$
We want to determine which two numbers need to be interchanged so that Y becomes 29.
Step 1: Simplify the original equation.
Start by solving the original equation:
$6 × 4 - 5 + \frac{9}{3} = Y$
24 – 5 + 3 = Y
24 – 5 = 19
19 + 3 = 22
So, Y = 22 in the original equation.
Step 2: Try swapping the numbers based on the options:
Option 1: Swap 5 and 3.
The new equation would be:
$6 × 4 - 3 + \frac{9}{5} = Y$
24 – 3 + 1.8 = Y
24 – 3 = 21
21 + 1.8 = 22.8 (This is not 29)
Option 2: Swap 4 and 5.
The new equation would be:
$6 × 5 - 4 + \frac{9}{3} = Y$
30 – 4 + 3 = Y
30 – 4 = 26
26 + 3 = 29
So, Y = 29 when we swap 4 and 5.
Final Answer:
Option 2: 4 and 5

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