106) In which of the following states of India is Padayani a ritual dance art form performed at Bhadrakali temple?
A) Karnataka
B) Maharashtra
C) Kerala
D) Tamil Nadu
107) __________defeated Mahmud Khilji and erected the tower of victory (Vijay Stambha) in Chittorgarh.
A) Prithviraj Chauhan
B) Jai Chand Gadhawak
C) Rana Sangram Singh
D) Rana Kumbha
108) G, M, P, V, Z and D are six members of a family. Z is the son of V. M is the brother of V. D and V are a married couple. P is the daughter of D. D is the sister of G.
How is Z related to P?
A) Mother
B) Sister
C) Brother
D) Father
109) In a certain code language,
‘good deeds pay’ is coded as ‘ag bi tr’,
‘pay all bills’ is coded as ‘od ez ag’,
‘all your deeds count’ is coded as ‘sn tr od um’.
(Note: All codes are two letter codes only)
What is the code for ‘count’ in the given code language?
A) ez
B) either ‘od’ or ‘tr’
C) either ‘sn’ or ‘um’
D) od
110) Five years ago, ages of father and his son were in the ratio 7:2. Five years hence, ages of the father and his son will be in the ratio 9:4. After how many years will the father’s age be twice the age of his son?
A) 8
B) 12
C) 9
D) 10
Explanation:Let’s solve this step by step.
Given:
– Five years ago, the ratio of the father’s age to the son’s age was 7:2.
– Five years hence, the ratio of the father’s age to the son’s age will be 9:4.
– We need to find after how many years the father’s age will be twice the son’s age.
Step 1: Let the current ages of the father and son be:
– Let the father’s current age be ( F ).
– Let the son’s current age be ( S ).
Step 2: Set up equations based on the given information:
»Five years ago:
Five years ago, the father’s age was ( F – 5 ) and the son’s age was ( S – 5 ). According to the problem, the ratio of their ages was 7:2:
Cross-multiply to get the equation:
2(F – 5) = 7(S – 5)
2F – 10 = 7S – 35
2F – 7S = -25 (Equation 1)
»Five years hence:
Five years hence, the father’s age will be ( F + 5 ) and the son’s age will be ( S + 5 ). According to the problem, the ratio of their ages will be 9:4:
Cross-multiply to get the equation:
4(F + 5) = 9(S + 5)
4F + 20 = 9S + 45
4F – 9S = 25 (Equation 2)
Step 3: Solve the system of equations:
We have two equations:
»1. ( 2F – 7S = -25 )
»2. ( 4F – 9S = 25 )
We can solve these equations by elimination or substitution. Let’s use the elimination method.
Multiply Equation 1 by 2 to make the coefficient of ( F ) the same in both equations:
2(2F – 7S) = 2(-25)
4F – 14S = -50 (Equation 3)
Now subtract Equation 2 from Equation 3:
(4F – 14S) – (4F – 9S) = -50 – 25
-14S + 9S = -75
-5S = -75
S = 15
Step 4: Find the father’s age:
Now that we know the son’s age ( S = 15 ), substitute this into Equation 1 to find the father’s age:
2F – 7(15) = -25
2F – 105 = -25
2F = 80
F = 40
Step 5: Find when the father’s age will be twice the son’s age:
We are asked to find after how many years the father’s age will be twice the son’s age. Let the number of years be ( x ). After ( x ) years, the father’s age will be ( F + x ) and the son’s age will be ( S + x ). The condition is that the father’s age is twice the son’s age:
F + x = 2(S + x)
Substitute the values ( F = 40 ) and ( S = 15 ):
40 + x = 2(15 + x)
40 + x = 30 + 2x
40 – 30 = 2x – x
10 = x
Final Answer:
The father’s age will be twice the son’s age after 10 years.