TS Polycet (Polytechnic) 2019 Previous Question Paper with Answers And Model Papers With Complete Analysis

Q). Total surface area of a hemisphere is
A) 2π r2
B) 3π r2
C) 4π r2
D) π r2

View Answer
B) 3π r2
Explanation: Total surface area = 3π r2

Q). If the radius of base of a cylinder is doubled and the height remains unchanged, then its curved surface area is
A) double
B) three times
C) four times
D) no change

View Answer
A) double
Explanation: r = 2r, h = h
Curved surface area = 2πrh
= 2π (2r) h
= 2(2πrh)

Q). If a right-angled triangle is revolved about its hypotenuse, then it will form a
A) Sphere
B) Cube
C) Cone
D) Cylinder

View Answer
C) Cone
Explanation: Cone

Q). tan 85° tan 65° tan 45° tan 25° tan 5° =
A) 1
B) 0
C) -1
D) None of these

View Answer
A) 1
Explanation: tan 85°.tan 65°.tan 45°.tan (90 – 65°).tan (90-85°)
= tan 85°.tan 65°.l.cot 65°.cot 85° = 1

Q). If sin 18° = cos x, then x =?
A) 73°
B) 37°
C) 72°
D) 84°

View Answer
C) 72°
Explanation: sin 18° = cos x
sin 18° = sin (90 -x)
90 -x = 18° => 90 – 18 = x = 72°

Q). \sqrt{(sec\theta-1)(sec\theta+1)} =
A) sec θ
B) tan θ
C) sin θ
D) cot θ

View Answer
B) tan θ
Explanation: \sqrt{sec^2\theta-1}= \sqrt{tan^2\theta-1}= tanθ

Q). If ∠A = 60°, then 3sin3A – 4sinA =
A) \frac{-7\sqrt3}8
B) \frac{\sqrt3}8
C) \frac{-7}8
D) \frac{7\sqrt3}8

View Answer
A) \frac{-7\sqrt3}8
Explanation: 3(sin 60°)3 – 4sin 60° = 3\;x\left(\frac{\sqrt3}2\right)3\;-\;4\;x\;\frac{\sqrt3}2
= \frac{3.3.\sqrt3}8\;-\;2\sqrt3 = \frac{9\sqrt3\;-\;16\;\sqrt3}8
= \frac{-7\sqrt3}8

Q). If a cos θ + b sin θ = p; a sin θ- b cos θ = q, then which of the following conditions is true?
A) a2 + b2 = p2 + q2
B) a2 + b2 = P2-q2
C) a2-b2 = p2 + q2
D) a2-b2=p2-q2

View Answer
A) a2 + b2 = p2 + q2
Explanation: a2cos2θ + b2sin2θ + 2ab sinθ cosθ = p2
a2sin2θ + b2cos2θ – 2ab sinθ cosθ = q2
a2 + b2 = p2 + q2

Q). If tan α = 1/2., tan β = 1/3, then (α+β)=
A) 30°
B) 60°
C) 45°
D) 0°

View Answer
C) 45°
Explanation: tanα = 1/2., tan β = 1/3,
Tan (α+β) = \frac{\tan\alpha\;+\tan\;\beta}{1-\tan\alpha.\tan\;\beta}
= \frac{\frac12+\frac13}{1-\;\frac16}=\frac{\frac{3+2}6}{\frac56} = 1
∴ (α+β) = 45°

Q). If the angle of elevation of the sun is 60°, then the ratio of the height of a tree with its shadow is
A) 1 : 1
B) 1 : √3
C) √3 : 1
D) None of these

View Answer
C) √3 : 1
Explanation: tan 60°= h/x
⇒ √3/1 = h/x ⇒ h : x = √3 : 1

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