TS Polycet (Polytechnic) 2019 Previous Question Paper with Answers And Model Papers With Complete Analysis

Q). If the system of equation x + 2y – 5 and 3x + ky + 15 = 0 has no solution, then k =
A) -6
B) 6
C) 3/2
D) 2/3

View Answer
B) 6
Explanation: No solution, so \frac{a1}{a2}=\frac{b1}{b2}\;\Rightarrow\;\frac13=\frac2k
=> k = 6

Q). If the system of equation 2x + 3y = 7 and (a + b) x + (2a – b) y = 21 has infinite number of solutions, then
A) a = 5, b = —1
B) a = 5, b = 1
C) a = — 1, b = 5
D) a = —1, b = —5

View Answer
B) a = 5, b = 1
Explanation: Infinite number of solutions,
\frac{a1}{a2}=\frac{b1}{b2}\;=\frac{c1}{c2}
\frac2{a+b\;}=\frac3{2a-b} = -7/-21
\frac2{a+b\;}  = 1/3 =>  a+\cancel b\;=\;6
2a-\cancel b\;=\;9
————————–
3a = 15 => a = 15/3 = 5
∴ b = 6-5 = 1

Q). If the system of equation 3x – 2y – 7 = 0 and 6x + ky + 11 = 0 has unique solution, then
A) k = 4
B) k ≠ 4
C) k = —4
D) k ≠ —4

View Answer
D) k ≠ —4
Explanation: Unique solution. So
3/6 ≠ -2/k
∴ k = -4

Q). The solution of 99x + 101y = 499 and 101x + 99y = 501 is
A) (-3, -2)
B) (3, -2)
C) (-2, 3)
D) (3, 2)

View Answer
D) (3, 2)
Explanation: 99x + 101y = 99(3) + 101(2)
= 297 + 202 = 499
101x + 99y =101(3) + 99(2)
= 303 + 198 = 501

Q). The-line x = 5y passes through
A) (1, 1)
B) (2, 3)
C) (0,0)
D) (1,5)

View Answer
C) (0,0)
Explanation: (0,0)

Q). Roots of X2+6x + 5 = 0 are:
A) 1, 5
B) -1, 5
C) -1, -5
D) 1, -5

View Answer
C) -1, -5
Explanation: X2 + 5x + x + 5 = 0 => x(x + 5) + 1(x + 5) = 0
=> (x +, 5) (x + 1) = 0 => x = -5 (or) -1

Q). If roots of X2 + kx + 3 = 0 are equal, then Value of ‘k’:
A) 2√3
B) -2√3
C) ± 2√3
D) ±3√2

View Answer
C) ± 2√3
Explanation: Roots are equal, b2 – 4ac = 0
k2 – 4.1.3 = 0 => k2 = 12
k = ± 2√3

Q). Discriminant of 2X2 -6x + 3 = 0 is:
A) 60
B) 12
C) 36
D) 24

View Answer
B) 12
Explanation: D = b2 – 4ac
= (-6)2-4.2.3
= 36- 24 = 12

Q). x2 + 7x + 12 =
A) (x + 3)(x-4)
B) (x + 3)(x + 4)
C) (x-3)(x-1)
D) None

View Answer
B) (x + 3)(x + 4)
Explanation: x2 + 7x+12
= x2 + 4x + 3x + 12
= x(x + 4) +3 (x + 4)
= (x + 3) (x + 4)

Q). 10th term of A.P.: 5, 1, -3, -7,………………………
A) -31
B) 31
C) -27
D) -35

View Answer
A) -31
Explanation: a = 5, d = —4, a10 = a + 9d = 5 + 9(-4)
= 5-36= -31

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