11)If the system of equation x + 2y – 5 and 3x + ky + 15 = 0 has no solution, then k =
View Answer
B) 6
Explanation:No solution, so
=> k = 6
12)If the system of equation 2x + 3y = 7 and (a + b) x + (2a – b) y = 21 has infinite number of solutions, then
A) a = 5, b = —1
B) a = 5, b = 1
C) a = — 1, b = 5
D) a = —1, b = —5
View Answer
B) a = 5, b = 1
Explanation:Infinite number of solutions,
= -7/-21
————————–
3a = 15 => a = 15/3 = 5
∴ b = 6-5 = 1
13)If the system of equation 3x – 2y – 7 = 0 and 6x + ky + 11 = 0 has unique solution, then
A) k = 4
B) k ≠ 4
C) k = —4
D) k ≠ —4
View Answer
D) k ≠ —4
Explanation:Unique solution. So
3/6 ≠ -2/k
∴ k = -4
14)The solution of 99x + 101y = 499 and 101x + 99y = 501 is
A) (-3, -2)
B) (3, -2)
C) (-2, 3)
D) (3, 2)
View Answer
D) (3, 2)
Explanation:99x + 101y = 99(3) + 101(2)
= 297 + 202 = 499
101x + 99y =101(3) + 99(2)
= 303 + 198 = 501
15)The-line x = 5y passes through
A) (1, 1)
B) (2, 3)
C) (0,0)
D) (1,5)
View Answer
C) (0,0)
Explanation:(0,0)
16)Roots of X2 +6x + 5 = 0 are:
A) 1, 5
B) -1, 5
C) -1, -5
D) 1, -5
View Answer
C) -1, -5
Explanation:X2 + 5x + x + 5 = 0 => x(x + 5) + 1(x + 5) = 0
=> (x +, 5) (x + 1) = 0 => x = -5 (or) -1
17)If roots of X2 + kx + 3 = 0 are equal, then Value of ‘k’:
A) 2√3
B) -2√3
C) ± 2√3
D) ±3√2
View Answer
C) ± 2√3
Explanation:Roots are equal, b2 – 4ac = 0
k2 – 4.1.3 = 0 => k2 = 12
k = ± 2√3
18)Discriminant of 2X2 -6x + 3 = 0 is:
View Answer
B) 12
Explanation:D = b2 – 4ac
= (-6)2 -4.2.3
= 36- 24 = 12
19)x2 + 7x + 12 =
A) (x + 3)(x-4)
B) (x + 3)(x + 4)
C) (x-3)(x-1)
D) None
View Answer
B) (x + 3)(x + 4)
Explanation:x2 + 7x+12
= x2 + 4x + 3x + 12
= x(x + 4) +3 (x + 4)
= (x + 3) (x + 4)
20)10th term of A.P.: 5, 1, -3, -7,………………………..
A) -31
B) 31
C) -27
D) -35
View Answer
A) -31
Explanation:a = 5, d = —4, a10 = a + 9d = 5 + 9(-4)
= 5-36= -31
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