TS TET Mathematics 8 Jan 2025 Shift 1 Solved Paper

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101) The predecessor of whole number 0 is
పూర్ణాంకం 0 కి ముందు సంఖ్య 1

A) 1
B) -1
C) 0
D) no predecessor
ముందు సంఖ్య ఉండదు

View Answer

D) no predecessor

Explanation:Whole numbers are 0, 1, 2, 3, …
0 is the smallest whole number, so it has no predecessor.
Correct Answer: (no predecessor)

102) The perimeters of a rectangle and a square are same. If the length and breadth of the rectangle are 32 cm and 28 cm respectively. Then, the area of the square is greater than area of the rectangle by (in sq. cm)
ఒక దీర్ఘచతురస్రం మరియు ఒక చతురస్రం యొక్క చుట్టుకొలతలు సమానం. దీర్ఘచతురస్రం యొక్క పొడవు మరియు వెడల్పులు వరుసగా 32 సెం.మీ మరియు 28 సెం.మీ. అయితే, ఆ చతురస్రం యొక్క వైశాల్యం దీర్ఘ చతురస్రం వైశాల్యం కంటే ఎంత ఎక్కువ (చ.సెం.మీ.లలో)?

A) 4
B) 32
C) 16
D) 8

View Answer

A) 4

Explanation:Let’s solve step-by-step.
Step 1: Given data
Rectangle: length $l = 32 \, \text{cm}$ , breadth $b = 28 \, \text{cm}$
Perimeter of rectangle:
$P_{\text{rect}} = 2 \times (l + b) = 2 \times (32 + 28) = 2 \times 60 = 120 \, \text{cm}$
Step 2: Perimeter of square
Given $P_{\text{rect}} = P_{\text{square}} = 120 \, \text{cm}$
Perimeter of square $= 4 \times \text{side}$
So, $4 \times s = 120$
$s = 30 \, \text{cm}$
Step 3: Areas
Area of rectangle:
$A_{\text{rect}} = l \times b = 32 \times 28 = 896 \, \text{cm}^2$
Area of square:
$A_{\text{sq}} = s^2 = 30 \times 30 = 900 \, \text{cm}^2$
Step 4: Difference
$A_{\text{sq}} - A_{\text{rect}} = 900 - 896 = 4 \, \text{cm}^2$
Final answer:
$\boxed{1}$

103) Number of lines of symmetry in a regular pentagon is
క్రమ పంచభుజిలో ఉండే సౌష్టవ రేఖల సంఖ్య

A) 4
B) 6
C) 7
D) 5

View Answer

D) 5

Explanation:A regular polygon has as many lines of symmetry as its number of sides.
A regular pentagon has 5 sides.

104) In the number 6 ? 5 ? 4, find the digit at “?’ place so that the difference between its place value is 5940.
సంఖ్య 6 ? 5 ? 4 లో “?” స్థానంలో అంకెను, దాని స్థాన విలువల మధ్య వ్యత్యాసం 5940 ఉండేలా కనుగొనండి

A) 7
B) 6
C) 8
D) 5

View Answer

B) 6

Explanation:Let’s understand the problem.
The number is: $6 ? 5 ? 4$ .
Let the first “?” digit (thousands place) be $a$ and the second “?” digit (tens place) be $b$ .
So the number is:
6 a 5 b 4
That means digits (from left to right) are:
– Ten-thousands place: 6
– Thousands place: a
– Hundreds place: 5
– Tens place: b
– Units place: 4
Step 1: Interpret “difference between its place value”
The phrase likely means the difference between the place value of digit $a$ and the place value of digit $b$ .
Place value of a = $a \times 1000$
Place value of b = $b \times 10$
The problem says: difference between these two place values = 5940.
Which is larger? Possibly $a$ ‘s place value minus $b$ ‘s place value = 5940, because $1000a > 10b$ for most $a, b$ digits (0–9).
$1000a - 10b = 5940$
Step 2: Solve equation
$1000a - 10b = 5940$
Divide by 10:
$100a - b = 594$
So:
$b = 100a - 594$
Step 3: Digit constraints
$a$ and $b$ are digits 0–9.
$b \ge 0$ ⇒ $100a - 594 \ge 0$ ⇒ $100a \ge 594$ ⇒ $a \ge 5.94$ ⇒ $a \ge 6$
$b \le 9$ ⇒ $100a - 594 \le 9$ ⇒ $100a \le 603$ ⇒ $a \le 6.03$ ⇒ $a \le 6$
So $a = 6$ only.
Then $b = 100 \times 6 - 594 = 600 - 594 = 6$ .
Thus $a=6, b=6$ .
Step 4: Check the other way?
Could it be $10b - 1000a = 5940$ ?
That would mean $10b - 1000a = 5940$ ⇒ $10b = 1000a + 5940$ ⇒ $b = 100a + 594$
That’s >594 for any $a$ , impossible since $b$ is a digit.So not possible.
So $a=6, b=6$ fits.
Step 5: Match with options
They ask: “find the digit at ‘?’ place” — possibly they mean the same digit for both placeholders? The given options are single digits (7, 6, 8, 5).
Since $a=6$ , the digit at “?” place is $6$ .
$\boxed{2}$

105) A hotel requires 7 litres of edible oil per day. If cost of one litre oil is ₹100, the cost of oil required by hotel for 31 days is
ఒక హోటల్ కు రోజుకు 7 లీటర్ల వంట నూనె అవసరం. ఒక లీటరు నూనె ధర ₹100 అయితే, ఆ హోటలు 31 రోజులకు అవసరమయ్యే నూనె ధర

A) ₹31000
B) ₹14700
C) ₹21700
D) ₹28700

View Answer

C) ₹21700

Explanation:Oil required per day = 7 litres
Cost per litre = ₹100
Cost per day = 7 × 100 = ₹700
For 31 days = 700 × 31 = ₹21700

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