TS TET Mathematics 9 Jan 2025 Shift 1 Solved Paper

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106) The mode of the numbers 9, 6, 4, 6, 3, 4, 3, 1, 5, 2, 1, 3 is:
సంఖ్యలు 9, 6, 4, 6, 3, 4, 3, 1, 5, 2, 1, 3 యొక్క బాహుళకం:

A) 4
B) 3
C) 6
D) 1

View Answer
B) 3

Explanation:Given numbers:
9, 6, 4, 6, 3, 4, 3, 1, 5, 2, 1, 3
Frequencies:
1 → 2 times
3 → 3 times
4 → 2 times
6 → 2 times
Mode = 3

107) The rational number that lies between \frac{5}{9} \text{ and } \frac{6}{7} from the following is
కింది వాటిలో \frac{5}{9} \text{ మరియు } \frac{6}{7} ల మధ్య ఉండే అకరణీయ సంఖ్య

A) \frac{15}{16}
B) \frac{2}{5}
C) \frac{13}{16}
D) \frac{15}{17}

View Answer
C) \frac{13}{16}

Explanation:A rational number between \frac{5}{9} and \frac{6}{7}
First convert to decimals to compare range:
\frac{5}{9} \approx 0.555\ldots
\frac{6}{7} \approx 0.857\ldots
We want a fraction between 0.555… and 0.857…
Check each option:
\frac{15}{16} = 0.9375 → greater than 0.857 → ❌ not in between
\frac{2}{5} = 0.4 → less than 0.555 → ❌
\frac{13}{16} = 0.8125 → between 0.555… and 0.857… ✅
\frac{15}{17} \approx 0.882 → slightly greater than 0.857 → ❌ (actually 15/17 = 0.88235…, greater than 6/7 ≈ 0.85714)
So only \frac{13}{16} works.

108) The no. of cubes with edge 3cm can be made from a cuboid of dimensions 15cm × 12cm × 9cm are
15సెం.మీ.× 12 సెం.మీ.× 9 సెం.మీ.కొలతలు కలిగిన దీర్ఘఘనం నుండి 3 సెం.మీ.అంచు ఉండేలా తయారు చేయగల ఘనాల సంఖ్య

A) 48
B) 24
C) 28
D) 60

View Answer
D) 60

Explanation: Dimensions of cuboid
= 15 × 12 × 9
Volume of cuboid
= 15 × 12 × 9 = 1620
Volume of one cube (edge 3 cm)
= 3 × 3 × 3 = 27
Number of cubes
= 1620 ÷ 27 = 60

109) The difference between 8563 and the number obtained by reversing its digits is
8563 మరియు దాని అంకెలను కుడి నుండి ఎడమకు రాయడంలో పొందిన సంఖ్యల మధ్య వ్యత్యాసం

A) 4905
B) 5115
C) 4995
D) 5015

View Answer
A) 4905

Explanation:Original number = 8563
Reversed number = 3658
Difference
= 8563 − 3658 = 4905

110) The number of \frac{1}{16} \text{ in } \frac{1}{2} is
\frac{1}{2} లో ఉన్న \frac{1}{16} ల సంఖ్య

A) 4
B) 8
C) 16
D) 2

View Answer
B) 8

Explanation:Number of \frac{1}{16} in \frac{1}{2}
= \frac{1}{2} ÷ \frac{1}{16}
= \frac{1}{2} × 16
= 8

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