TSSPDCL JLM Junior Lineman 15th Dec 2019 Exam Answer Key With Complete Explanation Previous Year Question Papers

TSSPDCL JLM Junior Lineman 15th Dec 2019 Exam Answer Key With Complete Explanation Previous Year Question Papers
Set Code: P
Booklet Code: D
Time : 2 Hours
Marks : 80 Instructions:
(i) Each question carries one mark.
SYLLABUS FOR THE POST OF JUNIOR LINEMAN JLM IN TSSPDCL
SCHEME OF EXAMINATION

Paper Subject No. of Questions Duration
(Minutes)
Maximum
Marks
1 I.T.I(Electrical
Trade) and General
Knowledge
80 Questions
(I.T.I(Electrical Trade):
65 Questions and
General Knowledge:
15 Questions)
120 80

Choose the correct or most appropriate answer from the given options to the following questions and darken, with Black Ball Point Pen only, the

corresponding digit (A), (B), (C) or (D) in the circle pertaining to the question

number concerned in the OMR Answer Sheet, separately supplied to you.
(iii) In this question paper for all questions the corresponding Telugu version

is also provided. In case of any discrepancy in the translation, the English version of the question will be considered as correct and final.

SECTION – A
1. Choose a correct statement from the following regarding current and potential transformers.
(A) Secondary of PT has single turn
(B) Primary of PT has single turn
(C) Secondary of CT has single turn
(D) Primary of CT has single turn

View Answer
(D) Primary of CT has single turn

2. In case of steam power station, water is taken to water turbine through a huge steel pipe from the valve house is known as _____
(A) surge tank
(B) penstock
(C) spillway
(D) draft tube

View Answer
(B) penstock

3. Wave wound d.c. generators provide :
(A) less current but more voltage
(B) more current but less voltage
(C) more current and more voltage
(D) less current and less voltage

View Answer
(A) less current but more voltage

4. A 3-phase supply is balanced if phase angle between two successive voltages is :
(A) 90°
(B) 180°
(C) 360°
(D) 120°

View Answer
(D) 120°

5.
The correct voltage equation of the above circuit is :
(A) Vx-Vs = V1+V2
(B) Vx+Vs=V1-V2
(C) Vx+Vs=V1+V2
(D) Vx-Vs =V1-V2

View Answer
(C) Vx+Vs=V1+V2
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