AP Polycet (Polytechnic) 2025 Previous Question Paper with Answers And Model Papers With Complete Analysis

AP Polycet (Polytechnic) 2025 Previous Question Paper with Answers And Model Papers With Complete Analysis
AP Polycet (Polytechnic) Previous Year Question Papers And Model Papers:
While preparing for AP Polycet (Polytechnic), candidates must also refer to the previous year question papers of the same. Scoring well in AP Polycet (Polytechnic) and understanding weaknesses and strengths in the respective sections.

AP Polycet (Polytechnic) Previous Year Question Papers can be found on this page in PDF format. Students taking the exam to get into some of the best Polytechnic colleges/institutes in the state of Andhra Pradesh may practice these papers to get a clear idea of the structure of the exam, marking scheme, important topics, etc.

AP Polycet Mock Test

AP POLYCET 2025
Section — A
MATHEMATICS

1)The points (1,5), (2,3) and (-2, -11) form a:

A) triangle

B) parallelogram

C) square

D) They are collinear

View Answer

A) triangle
Explanation:The points (1,5), (2,3), and (-2,-11) form a:
We check if the points are collinear using the slope method:
Slope of (1,5) and (2,3):
$m_1 = \frac{3 - 5}{2 - 1} = -2$

Slope of (2,3) and (-2,-11):
$m_2 = \frac{-11 - 3}{-2 - 2} = \frac{-14}{-4} = 3.5$

Since slopes are not equal, points are not collinear.
They form a triangle.
Answer: triangle

2)If 15 cotA = 8, then sinA = ?

A) $\dfrac{8}{15}$

B) $\dfrac{15}{17}$

C) $\dfrac{17}{15}$

D) $\dfrac{8}{17}$

View Answer

B) $\dfrac{15}{17}$

Explanation:If 15 cotA = 8, then sinA = ?
Let’s use Pythagoras.
Given:
$\cot A = \frac{8}{15} \Rightarrow \text{adjacent} = 8, \text{opposite} = 15$

Then, hypotenuse =
$\sqrt{8^2 + 15^2} = \sqrt{64 + 225} = \sqrt{289} = 17$

So,
$\sin A = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{15}{17}$

Answer: $\dfrac{15}{17}$

3)Evaluate $\dfrac{2 \tan 30°}{1 + \tan^2 30°}$

A) sin 60°

B) tan 60°

C) sin 30°

D) cot 60°

View Answer

B) tan 60°
Explanation:Evaluate $\dfrac{2 \tan 30°}{1 + \tan^2 30°}$

We use identity:
$\tan 2A = \frac{2\tan A}{1 + \tan^2 A}$

So this becomes:
$\tan 60° = \sqrt{3}$

Answer: tan 60°

4)Evaluate (sec A + tan A)(1 – sinA) = ?

A) sin A

B) cos A

C) csc A

D) sec A

View Answer

B) cos A
Explanation:Evaluate $(\sec A + \tan A)(1 - \sin A)$

Use identities:
$\sec A + \tan A = \frac{1}{\cos A} + \frac{\sin A}{\cos A} = \frac{1 + \sin A}{\cos A}$

Then:
$\frac{1 + \sin A}{\cos A} \cdot (1 - \sin A) = \frac{(1 - \sin^2 A)}{\cos A} = \frac{\cos^2 A}{\cos A} = \cos A$

Answer: cos A

5)Which of the following is true?

A) sin(A + B) = sinA + sin B

B) The value of sin θ increases as θ increases, 0° ≤ θ ≤ 90°

C) The value of cos θ increases as θ increases, 0° ≤ θ ≤ 90°

D) sin θ = cos θ for all values of θ

View Answer

B) The value of sin θ increases as θ increases, 0° ≤ θ ≤ 90°
Explanation:Which of the following is true?
False — sin(A + B) ≠ sinA + sinB
True — sinθ increases from 0 to 1 as θ increases from 0° to 90°
False — cosθ decreases in that interval
False — sin θ = cos θ only when θ = 45°
Answer: The value of sin θ increases as θ increases, 0° ≤ θ ≤ 90°

6)The angle formed by the line of sight with the horizontal when it is above the horizontal level is:

A) angle of elevation

B) angle of depression

C) right angle

D) none of these

View Answer

A) angle of elevation
Explanation:The angle formed by the line of sight above horizontal is:
Answer: angle of elevation

7)A ladder is leaned against a wall with angle of 60° with the ground and its foot is 6 feet away from the wall. Then the length of the ladder is:

A) 12 feet

B) 36) feet

C) 6 feet

D) 24 feet

View Answer

A) 12 feet
Explanation:Ladder against wall: angle = 60°, base = 6 ft
Use cosine:
$\cos 60° = \frac{6}{\text{hypotenuse}} = \frac{6}{x} \Rightarrow \frac{1}{2} = \frac{6}{x} \Rightarrow x = 12$

Answer: 12 feet

8)Two cars are seen from the top of a tower of height 75 m with angles of depression 30° and 45°. If the cars are on opposite sides of the tower along the same line, the distance between them is:

A) 75(√3+1) m

B) 75(√3-1) m

C) 75(√3+1) m

D) 75(√3-1) m

View Answer

A) 75(√3+1) m
Explanation:From top of tower: height = 75 m, angles = 30° and 45°
Use:
Distance at 30° = $75 \cot 30° = 75 \sqrt{3}$

Distance at 45° = $75 \cot 45° = 75$

Total distance =
$75 (\sqrt{3} + 1)$

Answer: 75(√3 + 1) m

9)The number of tangents a circle can have from a point outside the circle is:

A) one

B) two

C) three

D) four

View Answer

B) two
Explanation:Number of tangents from a point outside a circle:
Answer: two

10)The angle made by the tangent at any point of the circle with the radius at the point of contact is:

A) 0°

B) 45°

C) 60°

D) 90°

View Answer

D) 90°
Explanation:Angle between radius and tangent at contact point:
Answer: D. 90°

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AP POLYCET 2025 Section — A MATHEMATICS

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AP POLYCET 2025
Section — A
MATHEMATICS