A) virtual and erect
Explanation:The image formed by a plane mirror is always
→ virtual and erect
72) The distance between the pole and the principal focus of a spherical mirror is called:
A) image distance
B) object distance
C) focal length
D) radius of curvature
View Answer
C) focal length
Explanation:Distance between pole and principal focus
→ focal length
73) A diminished, virtual and erect image is formed by a
A) concave mirror
B) convex mirror
C) plane mirror
D) planoconcave mirror
View Answer
B) convex mirror
Explanation:A diminished, virtual, erect image is formed by
→ convex mirror
74) The mirror used by a dentist to see a large image of the teeth of the patients is
A) concave mirror
B) convex mirror
C) plane mirror
D) plano-convex mirror
View Answer
A) concave mirror
Explanation:Mirror used by dentists
→ concave mirror
75) A ray of light travelling in air enters obliquely into water. This light ray
A) bends away from the normal
B) passes through the normal at the surface of separation
C) bends towards the normal
D) travels straight without bending
View Answer
C) bends towards the normal
Explanation:Light bends towards the normal when entering water from air
→ bends towards the normal
76) The focal length of a spherical mirror is 10cm. Its radius of curvature is:
A) 10cm
B) 5cm
C) 20cm
D) 0.2cm
View Answer
C) 20cm
Explanation:
→ 20cm
77) An object placed between the principal focus and center of curvature of a convex lens forms an image:
A) beyond the center of curvature
B) at infinity
C) at the principal focus
D) between principal focus and center of curvature
View Answer
C) at the principal focus
Explanation:Object between F and 2F (focus and center of curvature) in convex lens → image is beyond 2F
→ beyond the center of curvature
78) The power of a lens is 4D.Its focal length is
A) 0.25cm
B) 2.5cm
C) 25cm
D) 0.025cm
View Answer
C) 25cm
Explanation:Power
→ 25cm
79) If the height of the image is equal to the height of an object placed near a spherical lens, then the magnification m is
A) less than 1
B) greater than 1
C) equal to 1
D) equal to zero
View Answer
C) equal to 1
Explanation:Image height = object height → magnification = 1
→ equal to 1
80) An object is placed at a distance of 30cm from a concave lens of focal length 20cm.
The image distance is:
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