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TET Paper 1 Mathematics Content Bits Previous year question Paper Key with solutions

TET Mock Test

106) If 3p+15 = 4p+10, then the value of p is:
3p + 15 = 4p + 10 అయితే, p విలువ:

A) $\frac{25}7$
B) 5
C) -5
D) $-\frac{25}7$

View Answer

B) 5

Explanation:
We are given the equation:3p + 15 = 4p + 10
Step 1: Move terms involving (p) to one side
First, subtract (3p) from both sides of the equation to eliminate (p) from the left-hand side:15 = p + 10
Step 2: Solve for (p)Now, subtract 10 from both sides to isolate (p):15 – 10 = pp = 5

107) Swati takes a loan of ₹6000 at 10% rate of interest. The interest she has to pay at the end of the year is:
స్వాతి 10% వడ్డీ రేటుతో ₹6000 రుణం తీసుకుంది. ఏడాది చివరిలో ఆమె చెల్లించాల్సిన వడ్డీ:

A) ₹720
B) ₹660
C) ₹550
D) ₹600

View Answer

D) ₹600

Explanation:To calculate the interest that Swati has to pay, we can use the Simple Interest formula:
{Simple Interest} = $\frac{P \times R \times T}{100}$ Where:
– ( P ) is the principal amount (₹6000),
– ( R ) is the rate of interest (10%),
– ( T ) is the time period in years (1 year).
Step 1: Substitute the values into the formula
{Simple Interest} = $\frac{6000 \times 10 \times 1}{100}$
Step 2: Calculate the interest
{Simple Interest} = $\frac{60000}{100}$
= 600

108) $18\div\frac34$ =

A) 13.5
B) 24
C) 16
D) $\frac1{24}$

View Answer

B) 24

Explanation:To solve the expression $18 \div \frac{3}{4}$ , we can rewrite division by a fraction as multiplication by its reciprocal.
Step 1: Rewrite the division as multiplication
$18 \div \frac{3}{4} = 18 \times \frac{4}{3}$
Step 2: Perform the multiplication
Now, multiply 18 by $\frac{4}{3}$ : $18 \times \frac{4}{3} = \frac{18 \times 4}{3} = \frac{72}{3}$ = 24

109) Supplementary angles among the following is:
కింది వాటిలో సంపూరక కోణాలు:

A) 35°, 135°
B) 15°, 75°
C) 115°, 65°
D) 95°, 65°

View Answer

C) 115°, 65°

Explanation:Supplementary angles are two angles whose sum is 180⁰

110) Degree of the term 9x²y²z² is:
పదం 9x²y²z² యొక్క పరిమాణం:

A) 2
B) 8
C) 4
D) 6

View Answer

D) 6

Explanation:The degree of a term in a polynomial is the sum of the exponents of the variables in that term.
For the term ( 9x²y²z² ), we have:
– The exponent of ( x ) is 2,
– The exponent of ( y ) is 2,
– The exponent of ( z ) is 2.
Now, add the exponents together:2 + 2 + 2 = 6

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