41)If the ratio of radii of two spheres is 2 : 3, then the ratio of their surface areas is
A) 3 : 2
B) 4 : 9
C) 9 : 4
D) 8 : 27
View Answer
B) 4 : 9
Explanation:r1 : r2 = 2:3
⇒ LSA1 : LSA2
= 4 πr1 2 : 4 πr2 2
= 22 :32
= 4:9:MsgIncorrect:
42)Ratio of volumes of a Cone, a Cylinder and a Hemi-sphere of same base radius and equal heights is ……………..
A) 1 : 2 : 3
B) 3 : 2 : 1
C) 1 : 3 : 2
D) 3 : 1 : 2
View Answer
C) 1 : 3 : 2
Explanation:Required ratio of volumes of a cone, cylinder and a hemi-sphere
=
πr
2 h : πr
2 h :
πr
2 h
=1/3 :1/1:2/3
= 1:3:2
43)The area of equilateral triangle is 36 √3 cm2 , then the perimeter is…………………. cm
View Answer
C) 36
Explanation:Area of equilateral △
le = 36√3
⇒ a
2 = 4 x 36
⇒a =
=2 x 6 = 12 cm
Perimeter of equilateral triangle
= 3 x side = 3 x 12 = 36 cm
44)If 3 tan A = 4 then sin A =
A) 3/4
B) 4/3
C) 4/5
D) 3/5
View Answer
C) 4/5
Explanation:tan A = 4/3
⇒ AC2 = 42 + 32
= 16 + 9 = 25
⇒ AC = 5
∴ Sin A = BC/CA= 4/5
45) =
A) 1/√3
B) √3
C) 1/2
D) 3
View Answer
B) √3
Explanation:
= tan2θ = tan.2.30°
= tan 60° = √3
46)tan 48° . tan 42° =
View Answer
B) 1
Explanation:tan 48° . tan (90° -48°)
= tan 48° . cot 48°
= tan 48° . 1/ tan 48°
= 1
47)(1 -cosθ) (1 + cosθ) =
A) sin2 θ
B) cos2 θ
C) tan2 θ
D) cot2 θ
View Answer
A) sin2 θ
Explanation:(1 – cosθ) (1 + cosθ)
= 1 – cos2 θ = sin2 θ
48)If tanθ -cotθ = 1 then tan2 θ + cot2 θ =
View Answer
D) 3
Explanation:Given that tan θ – cot θ = 1
We know that a2 + b2 = (a -b) 2 + 2ab tan2 θ + cot2 θ
= (tan θ – cot θ)2 + 2 tanθ . 1/tanθ
= 1+2.1
= 1+2
= 3
49)If x = a cosθ, y = b secθ ⇒
A) xy = a2 b2
B) x2 y2 = ab
C) x2 y2 = a2 b2
D) None
View Answer
C) x2 y2 = a2 b2
Explanation:x = a cosθ ⇒ cosθ = x/a
y = b secθ ⇒ secθ = y/b
cos2 θ . sec2 θ =1
⇒(x/a)2 (y/b)2 = 1
⇒ x2 y2 = a2 b2
50)Length of shadow of a 12 m high pole is 4√3 metres in the morning. What is the angle of elevation of the sun rays with the ground at that time?
A) 30°
B) 45°
C) 15°
D) 60°
View Answer
D) 60°
Explanation:From the figure
tanθ= AB/BC = 12/4√3 = 3/√3=√3
tanθ = tan 60° ⇒θ = 60°
∴Angle of elevation = θ = 60°
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