TS Polycet (Polytechnic) 2018 Previous Question Paper with Answers And Model Papers With Complete Analysis

Q). If a, b, c are in A.P., then b – a =
A) (a+c)/2
B) c-b
C) b2-1
D) a-b

View Answer
B) c-b

Q). If a, b, c are in G.P., then a/b =
A) b/a
B) b/c
C) c/b
D) c/a

View Answer
B) b/c

Q). Sum of natural numbers from 1 to 100
A) 4050
B) 10100
C) 5500
D) 5050

View Answer
D) 5050
Explanation: Sum of ’n’ terms = ∑n = n(n+1)/2
Sum of’100’tenms = ∑I00
= 100(100+1)/2
= 100×101/2
= 5050

Q). The co-ordinates of point which intersects the line joining the points (2, 3) and (4, 5) in the ratio 1 : 2 internally
A) (-8/3,11/3)
B) (8/3,11/3)
C) (8/3,-11/3)
D) None

View Answer
B) (8/3,11/3)
Explanation: Given points (2, 3) and (4, 5)
X1 y1 =
X2 y2
m1 : m2 = 1 : 2
Required point
= (\frac{m_{{}_1}x_2+m_2x_1}{m_{{}_1}+m_2}, \frac{m_{{}_1}y_2+m_2y_1}{m_{{}_1}+m_2})
= [ \frac{1(4)+2(2)}{1+2}, \frac{1(5)+2(3)}{1+2}]
=[ \frac{4+4}3, \frac{4+4}3] = (8/3,11/3)

Q). In the following equations, line passing through origin is
A) Y = mx
B) Y = mx-c
C) Y = cx+m
D) Y = c

View Answer
A) Y = mx

Q). The slope of the straight line ax + by + c = 0 is
A) a/b
B) b/a
C) –a/b
D) –b/a

View Answer
C) –a/b

Q). The area of triangle having the sides 3 cm, 4 cm, 5 cm
A) 4
B) 5
C) 6
D) 7

View Answer
C) 6
Explanation: Given a = 3, b = 4, c = 5
Perimeter of a △le = 3 + 4 + 5 = 12
2s = 12 ⇒ s = 6
s — a = 6-3 = 3
s-b=6-4=2
s-c = 6- 5 = 1
∴ Area of △le
= \sqrt{s(s-a)(s-b)(s-c)}
= \sqrt{6x3x2x1}
= \sqrt{6^2}
= 6

Q). The number of angles in a triangle is
A) 3
B) 4
C) 5
D) 6

View Answer
A) 3

Q). The angles of a triangle are in the ratio 1:2:3. Then the least angle is
A) 15°
B) 30°
C) 45°
D) 60°

View Answer
B) 30°

Q). The ratio of the corresponding sides of 7 two similar triangles is 5 : 3, then the ratio of the areas is
A) 5 : 3
B) 3 : 5
C) 25 : 9
D) 9 : 25

View Answer
C) 25 : 9
Explanation: Ratio of areas = 52 : 32 = 25 : 9

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