TS Polycet (Polytechnic) 2020 Previous Question Paper with Answers And Model Papers With Complete Analysis

21)Solution of the equations 7x + 5y = 12, 5x – 7y = -2 is not equal to

A)

B)

C)

D)

View Answer

A)
Explanation:7x+ 5y = 12 ————(1) 5x – 7y = -2 —————–(2) (1)x5-(2)x7 => 35x + 25y = 60 35x – 49y = -14 – + – ______________ 74y= 74 => y = 1 (1) => 7x + 5(1) = 12 =>7x + 5=12=>7x=7=>x=1 ∴ x = 1, y = 1 ∴ Solution of the given equation’s are not equal to option (1).

22)From the top of the tower 60 mts high the angle of depression of two objects due north and due south of the tower are 60° and 45°, then the distance between two objects is

A) 60 √3 m

B) ( 60+20 √3)m

C) (60+ √3-1)m

D) (60+ √3+1)m

View Answer

B) ( 60+20 √3)m
Explanation:In △ACD, Tan 60° = CD/AC √3 = 60/AC => AC = 60/√3 = 20√3m In △BCD, Tan 45° = CD/BC 1 = 60/BC => BC = 60m ∴ AB = AC + BC = ( 20+√3 + 60)m

23)Find the mode when median is 125.6 and mean is 128.

A) 120

B) 120.8

C) 125

D) 128

View Answer

B) 120.8
Explanation:Mode = ? Median = 125.6 Mean = 128 ∴ Mode.= 3 median – 2 mean = 3(125.6)-2(128) = 376.8 – 256 = 120.8

24)The median of the marks scored by 100 students in a 25 marks Unit test is

Marks 0-5 5-10 10-15 15-20 20-25
No. of students 10 18 42 13 7

A) 12

B) 12.3

C) 12.6

D) 12.7

View Answer

B) 12.3
Explanation:n/2 = 90/2 = 45 45 lies in the class = 10 — 15 ∴ Median class = 10 – 15; h = 5 n/2 – c.f median = l\\;+\\frac{n/2\\;-\\;c.f}f x h = 10\\;+\\frac{90/2\\;-\\;28}{42} x 5 = 10 + 17/42 x 5 = 10+85/42 = 10+2.023 = 12.023 = 12.3

25)A number chosen from 1 to 100. Find the probability that it is a prime number.

A) 1/2

B) -1/4

C) 1/4

D) -1/2

View Answer

C) 1/4
Explanation:n(S) = 100, n(A) = 25 ∴ P(A) = n(A)/n(S) = 25/100 = 1/4

26)In hundred numbers 20 are fours, 40 are fives, 30 are sixes remaining are tens arithmetic mean is

A) 3.5

B) 5.6

C) 4.7

D) 5.8

View Answer

B) 5.6
Explanation:Arithmetic mean = \\frac{20x-4x40x5+30x6+10x10}{100} \\frac{80+200+180+100}{100} = 560/100 = 5.6

27)If a coin is tossed 3 times, then the probability of getting at least one head is

A) 3/8

B) 5/8

C) 1/8

D) 7/8

View Answer

D) 7/8
Explanation:n(S) = 23 = 8 A = {(H HH), (H HT), (HTH), (T HH), (H T T), (T H T), (T T H)} = n (A) = 7 ∴ P(A) = n(A)/n(S) = 7/8

28)A bag contains 6 red balls, 12 green balls and 8 black balls. Find the probability that the ball drawn is either a black or a red ball.

A) 13/7

B) 1/13

C) 7/13

D) 1/7

View Answer

C) 7/13
Explanation:n(S) = 26C1 = 26 n(A) .= 8C1 = 8 P(A) = n(A)/ n(S) = 8/26 N(B) = 6C1 = 6 P(B) = n(B)/n(S) = 6/26 ∴ P(A u B) = P(A) + P(B) – P(A n B) = 8/26+6/26 -0 =14/26 = 7/13

29)If two dice are rolled simultaneously, then the probability that the numbers on them are different is

A) 5/6

B) 1/4

C) 1/2

D) 9/13

View Answer

A) 5/6
Explanation:n(S) = 62 = 36 n(A) = 30 ∴ P(A) = \\frac{n(A)}{n(S)} = 30/36 = 5/6

30)Ratio of volume of cylinder and cone whose radii are equal and having same heights

A) 1 : 3

B) 1 : 2

C) 3 : 1

D) 2 : 1

View Answer

C) 3 : 1
Explanation:Ratio =π r2h: 1/3 π r2h = 1 : 1/3 3 : 1
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