TS Polycet (Polytechnic) 2020 Previous Question Paper with Answers And Model Papers With Complete Analysis

Q) logxb – logxa = logxc – logxb
∴ ac =
A) a2
B) b2
C) c2
D) None

View Answer
B) b2
Explanation: logxb – logxa = logxc – logxb
=> logx(b/a) = logx(c/b)
=>b/a = c/b=> b2 = ac

Q) A = {P, O, L, Y, T, E, C, H, N, 1, Q}, B = {P, O, L, Y, C, E, T, 2020}, B – A =
A) {20}
B) {2020}
C) {40}
D) None

View Answer
B) {2020}
Explanation: A = {P, O, L, Y, T, E; C, H, N, I, Q} B = {P, O, L, Y, C, E, t 2020}
B -A = {P, O,- L, Y, C, E, T, 2020} -{P, 6, L, Y, T, E, C, H, N, I, Q)
= {2020}

Q) If (5, 2) is the solution of 2x + 5y = 20, ax -by = 0, then (a, b) =
A) (2, 5)
B) (5, 2)
C) (-2, 5)
D) (-5, 2)

View Answer
A) (2, 5)
Explanation: (5, 2) is the solution of
2x + 5y = 20, ax – by = 0, then
5a-2b = 0
Verify option (1)
(2, 5) =>5(2)-2(5) = 10-10 = 0

Q) If the system of equations x – y = 1, ax + y = 2 has unique solution, then
A) a = 1
B) a = -1
C) a ≠ 1
D) a ≠ -1

View Answer
D) a ≠ -1
Explanation: a1/a2≠b1/b2
=> 1/a ≠ -1/1 =>1/a ≠ -1 =>A ≠ 1

Q) If α, β are the roots of x2– 1 = 0, then α+ β =
A) 0
B) 1
C) -1
D) 2

View Answer
A) 0
Explanation: b2 — 1 = 0
a = 1, b = 0, c = —1
α + β = -b/a = – 0/1 = 0

Q) For the equation 2019x+2020y = 4040 when x = 0 the value of y =
A) 2020
B) 2019
C) 4
D) 2

View Answer
D) 2
Explanation: 2019x + 2020y = 4040
: x = 0 => 2019 (0) + 2020y = 4040
=>2020y=4040
=> y = 4040/2020 = 2

Q) Solution of the equations 7x + 5y = 12, 5x – 7y = -2 is not equal to
A) \frac{-22}{22}. \frac{14}{14}
B) \frac{33}{33}, \frac{44}{44}
C) \frac{77}{77}, \frac{13}{13}
D) \frac{16}{16}, \frac{15}{15}

View Answer
A) \frac{-22}{22}. \frac{14}{14}
Explanation: 7x+ 5y = 12 ————(1)
5x – 7y = -2 —————–(2)
(1)x5-(2)x7
=> 35x + 25y = 60
35x – 49y = -14
– + –
______________
74y= 74 => y = 1
(1) => 7x + 5(1) = 12
=>7x + 5=12=>7x=7=>x=1
∴ x = 1, y = 1
∴ Solution of the given equation’s are not equal to option (1).

Q) From the top of the tower 60 mts high the angle of depression of two objects due north and due south of the tower are 60° and 45°, then the distance between two objects is
A) 60 √3 m
B) ( 60+20 √3)m
C) (60+ √3-1)m
D) (60+ √3+1)m

View Answer
B) ( 60+20 √3)m
Explanation: In △ACD,
Tan 60° = CD/AC
√3 = 60/AC

=> AC = 60/√3 = 20√3m
In △BCD,
Tan 45° = CD/BC
1 = 60/BC => BC = 60m
∴ AB = AC + BC = ( 20+√3 + 60)m

Q) What is the probability of getting an even number in a single throw of a die?
A) \frac12
B) \frac13
C) \frac16
D) \frac56

View Answer
A) \frac12
Explanation: S= {1,2,3, 4, 5, 6} => n (S) = 6
A = {2, 4, 6} => n(A) = 3
∴ P(A) = n(A)/n(S) = 3/6 = 1/2

Q) Find the mode when median is 125.6 and mean is 128.
A) 120
B) 120.8
C) 125
D) 128

View Answer
B) 120.8
Explanation: Mode = ?
Median = 125.6
Mean = 128
∴ Mode.= 3 median – 2 mean
= 3(125.6)-2(128)
= 376.8 – 256
= 120.8
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