AP Polycet (Polytechnic) 2021 Previous Question Paper with Answers And Model Papers With Complete Analysis

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AP Polycet (Polytechnic) 2021 Previous Question Paper with Answers And Model Papers With Complete Analysis
AP Polycet (Polytechnic) Previous Year Question Papers And Model Papers:
While preparing for AP Polycet (Polytechnic), candidates must also refer to the previous year question papers of the same. Scoring well in AP Polycet (Polytechnic) and understanding weaknesses and strengths in the respective sections.

AP Polycet (Polytechnic) Previous Year Question Papers can be found on this page in PDF format. Students taking the exam to get into some of the best Polytechnic colleges/institutes in the state of Andhra Pradesh may practice these papers to get a clear idea of the structure of the exam, marking scheme, important topics, etc.

AP Polycet Mock Test


AP POLYCET
Section — A
MATHEMATICS

  1. AP Polycet 2021 Mathematics
  2. AP Polycet 2021 Physics
  3. AP Polycet 2021 Chemistry
1)△ABC~△PQR, if ∠A = 50°, then ∠Q + ∠R =

A) 130°

B) 40°

C) 80°

D) 140°

View Answer

A) 130°
Explanation:Given:
△ABC \~ △PQR and ∠A = 50°
In similar triangles, corresponding angles are equal, and the sum of angles in any triangle is 180°.
So:
∠A corresponds to ∠P → ∠P = 50°
Then, ∠Q + ∠R = 180° – ∠P = 180° – 50° = 130°
Correct answer: 130°
2)The point which is equidistant from the vertices of a triangle is called

A) incentre

B) orthocentre

C) centroid

D) circumcentre

View Answer

D) circumcentre
3)The number of tangents that can be drawn to a circle from a point lying on the circle is

A) 1

B) 0

C) 2

D) infinite

View Answer

A) 1
4)The total surface are of a cuboid of length 'l, breadth 'b' and height 'h' in square units is

A) lbh

B) 2h(l+b)

C) 2(lb+bh+lh)

D) 2(1+b)

View Answer

C) 2(lb+bh+lh)
5)With usual notation, if r=7 and h=10 cm in a cone, then its lateral height (approximately) 1 =

A) 13.4 cm

B) 10.3 cm

C) 18.2 cm

D) 12.2 cm

View Answer

D) 12.2 cm
Explanation:We are given:
Radius r = 7 cm
Height h = 10 cm
We need to find the lateral height (also called slant height), denoted by l
Shortcut Formula for slant height of a cone:
l = \sqrt{r^2 + h^2}
l = \sqrt{7^2 + 10^2} = \sqrt{49 + 100} = \sqrt{149} \approx 12.2\ \text{cm}
Final Answer: D. 12.2 cm
6)If the diameter of a sphere is d, then its volume is

A) \frac16\mathrm{πd}^3

B) \frac43\mathrm{πd}^3

C) \frac1{24}\mathrm{πd}^3

D) \frac13\mathrm{πd}^3

View Answer

A) \frac16\mathrm{πd}^3
7)The sharpened edge of the pencil gives an idea about the

A) circle

B) cone

C) rectangle

D) none of these

View Answer

B) cone
8)If tanθ + cotθ = 2, then tan2θ+ cot2θ=

A) 4

B) 2

C) 6

D) 1

View Answer

B) 2
Explanation:We are given:
\tan\theta + \cot\theta = 2
Shortcut Trick:
Use the identity:
\tan^2\theta + \cot^2\theta = (\tan\theta + \cot\theta)^2 - 2
Substitute:
(\tan\theta + \cot\theta)^2 = 2^2 = 4
\tan^2\theta + \cot^2\theta = 4 - 2 = 2
Final Answer: 2
9)If tanθ = \frac1{\sqrt3} then value of cosθ is

A) \frac12

B) \frac{\sqrt3}2

C) \frac2{\sqrt3}

D) √3

View Answer

B) \frac{\sqrt3}2
Explanation:We are given:
\tan\theta = \frac{1}{\sqrt{3}}
Shortcut Method:
Recall the standard value:
\tan 30^\circ = \frac{1}{\sqrt{3}} \Rightarrow \theta = 30^\circ
Now, use:
\cos 30^\circ = \frac{\sqrt{3}}{2}
Final Answer: \frac{\sqrt{3}}{2}
10)If sinθ = \frac{12}{13} then tanθ =

A) \frac{13}5

B) \frac5{12}

C) \frac{13}{12}

D) \frac{12}5

View Answer

D) \frac{12}5
Explanation:We are given:
\sin\theta = \frac{12}{13}
Shortcut Method: Use Pythagorean Triplet
If \sin\theta = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{12}{13},
then use the Pythagorean identity:
\text{Adjacent} = \sqrt{13^2 - 12^2} = \sqrt{169 - 144} = \sqrt{25} = 5
Now,
\tan\theta = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{12}{5}
Final Answer: \frac{12}{5}
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