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NMMS Exam 2017 Previous Year Question Paper with Answers And Complete Analysis With Key For Practice Test Paper

NMMS Exam Online Mock Test

Q). When 0.4 : x :: 24 : 3, then x =
A) 0.05
B) 0.6
C) 0.7
D) 0.8

View Answer

A) 0.05
Explanation: $\frac{0.4}x=\frac{24}3$

= $\frac{0.4x3}{24}=x$

= $\frac{0.4}8=x$

= $\frac4{80}=x$

= $x=\frac1{20}=0.05$

Q). Multiply $\left(-5x^2y\right)\left(-\frac23xy^2z\right)\left(\frac8{15}xyz^2\right)and\left(-\frac14z\right)$
A) $\frac23xy^2z^2$
B) $\frac13x^2y^3z^3$
C) $-\frac49x^4y^4z^4$
D) $\frac16x^4y^5z^6$
A) A
B) B
C) C
D) D

View Answer

C) C
Explanation: $\left(-5x^2y\right)\left(-\frac23xy^2z\right)\left(\frac8{15}xyz^2\right)and\left(-\frac14z\right)$

$-\frac49x^4y^4z^4$

Q). Simplify $\left\{\left(\frac23\right)^2\right\}^{-3}÷\left\{\left(-\frac34\right)^2\right\}^{-2}$ =
A) 48
B) 3.6
C) -14
D) 5/6

View Answer

B) 3.6
Explanation: $\left\{\left(\frac23\right)^2\right\}^{-3}+\left\{\left(-\frac34\right)^2\right\}^{-2}$

$\left\{\frac49\right\}^{-3\;}+\left\{\frac9{16}\right\}^{-2}=\;\left\{\frac94\right\}^3+\left\{\frac9{16}\right\}^{-2}$

$\frac{9x9x9x9x9}{4\;x\;4\;x\;4\;x\;4\;x\;4\;x\;4\;x\;4}$

Q). if $\left(\frac35\right)^4+\left(\frac35\right)^3=\left(\frac35\right)^{2n-1}$ , then n=
A) 4
B) 3
C) 2
D) 5

View Answer

A) 4
Explanation: $\left(\frac35\right)^4+\left(\frac35\right)^3=\left(\frac35\right)^{2n-1}$

On both sides bases ,so powers most be equal.
2n – 1 = 7
2n = 7 + 1 = 8
N=8/2 =4

Q). if x – 1/x then $x^4+\frac1{x^4}$ =
A) 146
B) 119
C) 125
D) 110

View Answer

B) 119
Explanation: $x^4+\frac1{x^4}$

= 121-2 = 119

Q). In the given figure, find the value of x°.

A) 90°
B) 60°
C) 75°
D) 80°

View Answer

A) 90°
Explanation: x° = 40° + 50°
x° = 90°

Q). In the given figure, AB || CD and EA || DF, then the value of x° + y° is

A) 30°
B) 45°
C) 65°
D) 50°

View Answer

B) 45°

Q). In the given figure, the value of ∠A+∠B+∠C+∠D+∠E is

A) 180
B) 165
C) 120
D) 100

View Answer

A) 180
Explanation: Sum of the interior angles of a pentagon (star) is 5 x 36° = 180°

Q). In the given figure, the value of x° is

A) 104°
B) 84°
C) 96°
D) 121°

View Answer

C) 96°
Explanation: In the figure,
∠ABD + ∠ABC = 180°
138° + ∠ABC = 180°
∠ABC = 180°- 138° =42°’
In the figure ∠B = ∠A = 42° Sum of angles in a triangle is 180°
∠A + ∠B + x° = 180°
x° = 180 – (42 + 42)
= 180 – 84 = 96°

Q). In the given figure, the value of x° is

A) 30°
B) 45°
C) 36°
D) 48°

View Answer

A) 30°
Explanation: From the figure,
a° + 5a° = 180°
6a°= 180°
a° = 180/6 =30°
4a° = 4×30° = 120
Sum of the angles in a triangle is 180°.
x° + 4a° + a° = 180
x° + 120° + 30° =180°
x° + 150° = 180°
x° = 180° – 150° = 30°
∴x° = 30°

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NMMS Exam 2017 Previous Year Question Paper with Answers And Complete Analysis With Key For Practice Test Paper

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