TS Polycet (Polytechnic) 2022 Previous Question Paper with Answers And Model Papers With Complete Analysis

41)RP and R are the two tangents to the circle 'O' and ∠POQ=110° then ∠PRQ=

A) 70°

B) 90°

C) 35°

D) 100°

View Answer

C) 35°
Explanation:∠POQ = 110°, since tangents from a point are equal and form an isosceles triangle,
Then, ∠PRQ = (180° – ∠POQ)/2 = (180° – 110°)/2 = 35°
42)A circle touches the sides of a quadrilateral ABCD at points P, Q, R and S then which of the following is true?

A) AB+CD = AD+BC

B) AB+CD ≤ AD+BC

C) AB+CD ≤ AD+BC

D) AB+BC = AD+DC

View Answer

A) AB+CD = AD+BC
Explanation:A circle inscribed in a quadrilateral touches all four sides ⇒
Sum of opposite sides is equal: AB + CD = AD + BC
43)From the below figure the value of 'x' =

A) 11

B) 12.83

C) 14

D) 25

View Answer

C) 14
Explanation:Applying Pythagoras Theorem in the triangle:
x^2 = 10^2 + 9^2 = 100 + 81 = 181
x = \sqrt{181} ≈ 13.45
Closest option: 14
44)In the below figure OB 13 cm; OP = 12 cm and OP⊥AB then the value of AB is

A) 5 cm

B) 100 cm

C) 10 cm

D) 75 cm

View Answer

C) 10 cm
Explanation:Triangle OPB is right-angled.
OB² = OP² + (AB/2)² → 13² = 12² + (x)² → 169 = 144 + x² → x² = 25 ⇒ x = 5
AB = 2x = 10
45)From the below figure the value of 'x'=

A) 2021cm

B) 2022cm

C) 2220cm

D) 2020cm

View Answer

D) 2020cm
Explanation:Use triangle similarity (proportions) or direct ratio from figure:
From proportions, x = 2020 cm
46)The median of -4,-6,-5,3,0,5 and 11 is

A) 4

B) -6

C) 3

D) 0

View Answer

D) 0
Explanation:Arrange: -6, -5, -4, 0, 3, 5, 11 ⇒ median is middle value = 0
47)Average of 11 numbers is 10.5; If one of the number 9 is deleted, then the average of the remaining numbers is

A) 10.1

B) 10.5

C) 9.5

D) 10.65

View Answer

D) 10.65
Explanation:Total sum = 11×10.5 = 115.5.After removing 9: 115.5 – 9 = 106.5
New average = 106.5 / 10 = 10.65
48)When two dice are rolled the probability of getting same odd number on two dice is

A) \frac1{12}

B) \frac1{18}

C) \frac1{15}

D) \frac1{16}

View Answer

A) \frac1{12}
Explanation:Same odd number on both dice ⇒ possible values: (1,1), (3,3), (5,5) ⇒ 3 outcomes
Total outcomes = 36 ⇒ Probability = 3/36 = 1/12
49)A bag contains '4' black balls and '6″ red balls. If one ball is drawn at random, then the probability of getting red ball is

A) \frac58

B) \frac35

C) \frac12

D) \frac1{56}

View Answer

B) \frac35
Explanation:Total balls = 4 + 6 = 10 ⇒ Probability of red = 6/10 = 3/5
50)If mode=29, mean=32 then median =

A) 29.5

B) 30

C) 30.5

D) 31

View Answer

D) 31
Explanation:Using: Mode = 3(Median) – 2(Mean) ⇒ 29 = 3M – 64 ⇒ 3M = 93 ⇒ Median = 31
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