Which of the following rational numbers has terminating decimal expansion?
Correct
A rational number has a terminating decimal if its denominator (after simplification) has only 2 and/or 5 as prime factors. : 40 = 2³ × 5 → TerminatingOthers (35, 21, 15) have 3 or 7 → Non-terminating
Answer:
Incorrect
A rational number has a terminating decimal if its denominator (after simplification) has only 2 and/or 5 as prime factors. : 40 = 2³ × 5 → TerminatingOthers (35, 21, 15) have 3 or 7 → Non-terminating
Answer:
Unattempted
A rational number has a terminating decimal if its denominator (after simplification) has only 2 and/or 5 as prime factors. : 40 = 2³ × 5 → TerminatingOthers (35, 21, 15) have 3 or 7 → Non-terminating
Answer:
Question 2 of 120
2. Question
1 points
Category: Polycet Mathematics
Which of the following is not an irrational number?
Correct
are irrational, which is rational
Answer:
Incorrect
are irrational, which is rational
Answer:
Unattempted
are irrational, which is rational
Answer:
Question 3 of 120
3. Question
1 points
Category: Polycet Mathematics
If p and q are two positive integers such that p=a3b2 and q=ab3, where a and b are prime numbers, then HCF(p,q) is
Correct
Given:
p = a³b2
q = ab³
HCF = lowest powers of common primes:
Incorrect
Given:
p = a³b2
q = ab³
HCF = lowest powers of common primes:
Unattempted
Given:
p = a³b2
q = ab³
HCF = lowest powers of common primes:
Question 4 of 120
4. Question
1 points
Category: Polycet Mathematics
The sum of exponents of the prime factors in the prime factorization of 196 is
Correct
196 = 2² × 7² → sum of exponents = 2 + 2 = 4
Incorrect
196 = 2² × 7² → sum of exponents = 2 + 2 = 4
Unattempted
196 = 2² × 7² → sum of exponents = 2 + 2 = 4
Question 5 of 120
5. Question
1 points
Category: Polycet Mathematics
According to the fundamental theorem of arthimetic, if p (a prime number) divides a2, where a is +ve integer, then
Correct
If a prime p divides a2, then p must divide a (from Fundamental Theorem of Arithmetic)
Incorrect
If a prime p divides a2, then p must divide a (from Fundamental Theorem of Arithmetic)
Unattempted
If a prime p divides a2, then p must divide a (from Fundamental Theorem of Arithmetic)
Question 6 of 120
6. Question
1 points
Category: Polycet Mathematics
If log+log= log(a+b), then
Correct
Use log laws:
So, log(a+b) = 0 ⇒ a+b = 1
Incorrect
Use log laws:
So, log(a+b) = 0 ⇒ a+b = 1
Unattempted
Use log laws:
So, log(a+b) = 0 ⇒ a+b = 1
Question 7 of 120
7. Question
1 points
Category: Polycet Mathematics
Which of the following collections is not a set?
Correct
“A collection of ten most talented writers of India” is not well-defined (subjective) → not a set
Incorrect
“A collection of ten most talented writers of India” is not well-defined (subjective) → not a set
Unattempted
“A collection of ten most talented writers of India” is not well-defined (subjective) → not a set
Question 8 of 120
8. Question
1 points
Category: Polycet Mathematics
Match the following:
a) Null set
(i) {x:x is a real number}
b) singleton set
(ii) (x:x is a whole number and x<0}
c) Infinite set
(iii) {x:x is an even prime number}
Correct
a) Null set → (ii) {x: x is a whole number and x < 0} = Ø
b) Singleton set → (iii) {x: x is an even prime number} = {2}
c) Infinite set → (i) {x: x is a real number}
Answer:A-(ii), B-(iii), C-(i)
Incorrect
a) Null set → (ii) {x: x is a whole number and x < 0} = Ø
b) Singleton set → (iii) {x: x is an even prime number} = {2}
c) Infinite set → (i) {x: x is a real number}
Answer:A-(ii), B-(iii), C-(i)
Unattempted
a) Null set → (ii) {x: x is a whole number and x < 0} = Ø
b) Singleton set → (iii) {x: x is an even prime number} = {2}
c) Infinite set → (i) {x: x is a real number}
Answer:A-(ii), B-(iii), C-(i)
Question 9 of 120
9. Question
1 points
Category: Polycet Mathematics
If A and B are disjoint sets, then
Correct
Disjoint sets → no common elements → intersection = empty set
Answer:A ∩ B = Φ
Incorrect
Disjoint sets → no common elements → intersection = empty set
Answer:A ∩ B = Φ
Unattempted
Disjoint sets → no common elements → intersection = empty set
Answer:A ∩ B = Φ
Question 10 of 120
10. Question
1 points
Category: Polycet Mathematics
In a class of 60 students, 45 students like music, 50 students like dance and 5 students like neither. Then the number of students in the class who like both music and dance is
Correct
Let M = students liking music = 45
D = dance = 50
Total = 60, 5 like neither → 55 like music or dance
Use:
n(M ∪ D) = n(M) + n(D) – n(M ∩ D)
→ 55 = 45 + 50 – x → x
= 40
Incorrect
Let M = students liking music = 45
D = dance = 50
Total = 60, 5 like neither → 55 like music or dance
Use:
n(M ∪ D) = n(M) + n(D) – n(M ∩ D)
→ 55 = 45 + 50 – x → x
= 40
Unattempted
Let M = students liking music = 45
D = dance = 50
Total = 60, 5 like neither → 55 like music or dance
Use:
n(M ∪ D) = n(M) + n(D) – n(M ∩ D)
→ 55 = 45 + 50 – x → x
= 40
Question 11 of 120
11. Question
1 points
Category: Polycet Mathematics
If A and B are two sets such that AUB=A∩B, then which of the following is correct?
Correct
If A ∪ B = A ∩ B, this means every element in A is also in B and vice versa, i.e., A = B.
Incorrect
If A ∪ B = A ∩ B, this means every element in A is also in B and vice versa, i.e., A = B.
Unattempted
If A ∪ B = A ∩ B, this means every element in A is also in B and vice versa, i.e., A = B.
Question 12 of 120
12. Question
1 points
Category: Polycet Mathematics
Which of the following is not a polynomial?
Correct
A, B, and C are polynomials.D: → contains x-1, which is not allowed in polynomials.
Answer:
Incorrect
A, B, and C are polynomials.D: → contains x-1, which is not allowed in polynomials.
Answer:
Unattempted
A, B, and C are polynomials.D: → contains x-1, which is not allowed in polynomials.
Answer:
If the sum of the zeros of the quadratic polynomial kx2+2x+3k is equal to the product of its zeroes, then the value of k is
Correct
Given:
Polynomial: kx2 + 2x + 3k Sum of roots = , Product =
Set:
Answer:
Incorrect
Given:
Polynomial: kx2 + 2x + 3k Sum of roots = , Product =
Set:
Answer:
Unattempted
Given:
Polynomial: kx2 + 2x + 3k Sum of roots = , Product =
Set:
Answer:
Question 15 of 120
15. Question
1 points
Category: Polycet Mathematics
Number of zeroes of the polynomial in the graph shown is
Correct
From the graph: The polynomial crosses the x-axis at 3 points, so it has 3 real zeroes.
Answer:3
Incorrect
From the graph: The polynomial crosses the x-axis at 3 points, so it has 3 real zeroes.
Answer:3
Unattempted
From the graph: The polynomial crosses the x-axis at 3 points, so it has 3 real zeroes.
Answer:3
Question 16 of 120
16. Question
1 points
Category: Polycet Mathematics
The value of k for which the pair of linear equations ky-y=2 and 6x-2y=3 has a unique solution, is
Correct
Given equations:
kx – y = 2
6x – 2y = 3
For unique solution, the ratio of coefficients must not be equal:
Check:
Answer:k ≠ 3
Incorrect
Given equations:
kx – y = 2
6x – 2y = 3
For unique solution, the ratio of coefficients must not be equal:
Check:
Answer:k ≠ 3
Unattempted
Given equations:
kx – y = 2
6x – 2y = 3
For unique solution, the ratio of coefficients must not be equal:
Check:
Answer:k ≠ 3
Question 17 of 120
17. Question
1 points
Category: Polycet Mathematics
The pair of equations y=7 and y=-7 has
Correct
y = 7 and y = -7 are parallel lines, never intersect →
Answer:no solution
Incorrect
y = 7 and y = -7 are parallel lines, never intersect →
Answer:no solution
Unattempted
y = 7 and y = -7 are parallel lines, never intersect →
Answer:no solution
Question 18 of 120
18. Question
1 points
Category: Polycet Mathematics
If the sum of the ages of a father and his son is 65 years and twice the difference of their ages is 50 years, then the age of the father in years is
Correct
Let father’s age = x, son’s = y
Given:
x + y = 65
2(x – y) = 50 ⇒ x – y = 25
Solve:
Add equations:
→ 2x = 90 ⇒ x = 45
Answer:45
Incorrect
Let father’s age = x, son’s = y
Given:
x + y = 65
2(x – y) = 50 ⇒ x – y = 25
Solve:
Add equations:
→ 2x = 90 ⇒ x = 45
Answer:45
Unattempted
Let father’s age = x, son’s = y
Given:
x + y = 65
2(x – y) = 50 ⇒ x – y = 25
Solve:
Add equations:
→ 2x = 90 ⇒ x = 45
Answer:45
Question 19 of 120
19. Question
1 points
Category: Polycet Mathematics
The 15th term of an AP=10,-5,0,5….. is
Correct
AP: 10, -5, 0, 5…
This seems wrong because 10 to -5 is a difference of -15, not an AP. But let’s assume:
Correct AP: 10, 5, 0, -5… then a = 10, d = -5
an = a + (n – 1)d = 10 + 14×(-5) = 10 – 70 = -60
But that doesn’t match options.
If AP is -5, 0, 5…, then a = -5, d = 5
15th term = -5 + 14×5 = 65
Incorrect
AP: 10, -5, 0, 5…
This seems wrong because 10 to -5 is a difference of -15, not an AP. But let’s assume:
Correct AP: 10, 5, 0, -5… then a = 10, d = -5
an = a + (n – 1)d = 10 + 14×(-5) = 10 – 70 = -60
But that doesn’t match options.
If AP is -5, 0, 5…, then a = -5, d = 5
15th term = -5 + 14×5 = 65
Unattempted
AP: 10, -5, 0, 5…
This seems wrong because 10 to -5 is a difference of -15, not an AP. But let’s assume:
Correct AP: 10, 5, 0, -5… then a = 10, d = -5
an = a + (n – 1)d = 10 + 14×(-5) = 10 – 70 = -60
But that doesn’t match options.
If AP is -5, 0, 5…, then a = -5, d = 5
15th term = -5 + 14×5 = 65
Question 20 of 120
20. Question
1 points
Category: Polycet Mathematics
If the first and fourth terms of a GP are 1 and 27 respectively, then the common ratio is
Correct
First term a = 1,
fourth term = ar3 = 27
→ r3 = 27 ⇒ r = 3
Incorrect
First term a = 1,
fourth term = ar3 = 27
→ r3 = 27 ⇒ r = 3
Unattempted
First term a = 1,
fourth term = ar3 = 27
→ r3 = 27 ⇒ r = 3
Question 21 of 120
21. Question
1 points
Category: Polycet Mathematics
If a,b,c are in AP and x, y, z are in GP, then the value of x(b-c)y(c-a)z(a-b) is
Correct
If a, b, c are in AP:
If x, y, z are in GP: y2 = xz
Expression:
Take logs:
Incorrect
If a, b, c are in AP:
If x, y, z are in GP: y2 = xz
Expression:
Take logs:
Unattempted
If a, b, c are in AP:
If x, y, z are in GP: y2 = xz
Expression:
Take logs:
Question 22 of 120
22. Question
1 points
Category: Polycet Mathematics
The distance of the point p(2,3) from the x-axis is (in units)
Correct
Distance from x-axis = y-coordinate = 3 units
Incorrect
Distance from x-axis = y-coordinate = 3 units
Unattempted
Distance from x-axis = y-coordinate = 3 units
Question 23 of 120
23. Question
1 points
Category: Polycet Mathematics
The quadrant in which the point divides the line segment joining the points (7,-6) and (3,4) in the ratio 1:2 internally lies, is
Correct
Use section formula:
This lies in the 4th quadrant
Incorrect
Use section formula:
This lies in the 4th quadrant
Unattempted
Use section formula:
This lies in the 4th quadrant
Question 24 of 120
24. Question
1 points
Category: Polycet Mathematics
The triangle formed by the vertices A(-4,0) and c(0,3) is
Correct
To determine the type of triangle formed by the vertices A(-4, 0), B(0, 0), and C(0, 3), let’s analyze the side lengths and angles.
Step 1: Identify the Coordinates
– A(-4, 0)
– B(0, 0)
– C(0, 3)
Step 2: Calculate the Side Lengths
Using the distance formula:
– 1. Length of :
– 2. Length of :
– 3. Length of :
Step 3: Check the Type of Triangle
– Isosceles Triangle: At least two sides are equal. Here, all sides are unequal (), so it is not isosceles.
– Equilateral Triangle: All sides are equal. Not applicable here.
– Scalene Triangle: All sides are unequal. This is true, but we also need to check angles.
– Right-Angled Triangle: Check if the sides satisfy the Pythagorean theorem:
Since , the triangle is right-angled at .
Conclusion
The triangle is right-angled at .
Incorrect
To determine the type of triangle formed by the vertices A(-4, 0), B(0, 0), and C(0, 3), let’s analyze the side lengths and angles.
Step 1: Identify the Coordinates
– A(-4, 0)
– B(0, 0)
– C(0, 3)
Step 2: Calculate the Side Lengths
Using the distance formula:
– 1. Length of :
– 2. Length of :
– 3. Length of :
Step 3: Check the Type of Triangle
– Isosceles Triangle: At least two sides are equal. Here, all sides are unequal (), so it is not isosceles.
– Equilateral Triangle: All sides are equal. Not applicable here.
– Scalene Triangle: All sides are unequal. This is true, but we also need to check angles.
– Right-Angled Triangle: Check if the sides satisfy the Pythagorean theorem:
Since , the triangle is right-angled at .
Conclusion
The triangle is right-angled at .
Unattempted
To determine the type of triangle formed by the vertices A(-4, 0), B(0, 0), and C(0, 3), let’s analyze the side lengths and angles.
Step 1: Identify the Coordinates
– A(-4, 0)
– B(0, 0)
– C(0, 3)
Step 2: Calculate the Side Lengths
Using the distance formula:
– 1. Length of :
– 2. Length of :
– 3. Length of :
Step 3: Check the Type of Triangle
– Isosceles Triangle: At least two sides are equal. Here, all sides are unequal (), so it is not isosceles.
– Equilateral Triangle: All sides are equal. Not applicable here.
– Scalene Triangle: All sides are unequal. This is true, but we also need to check angles.
– Right-Angled Triangle: Check if the sides satisfy the Pythagorean theorem:
Since , the triangle is right-angled at .
Conclusion
The triangle is right-angled at .
Question 25 of 120
25. Question
1 points
Category: Polycet Mathematics
If A(-1,2),B(4,0) and c(3,1) are three vertices of a parallelogram, then the fourth vertex is
Correct
Let D be the fourth vertex.
Using vector method:
A + C − B = D
(-1,2) + (3,1) − (4,0) = (-2,3) → No option.
Try: D = A + B − C = (-1,2) + (4,0) − (3,1) = (0,1) → also not listed.
Try: Using diagonals: AC and BD bisect each other
Midpoint of AC = (1, 1.5), so midpoint of BD must also be (1, 1.5)
From B(4,0): Let D(x,y)
Midpoint = ((4+x)/2, (0+y)/2) = (1, 1.5) → x = -2, y = 3
→ D = (-2,3) → not listed
Try again:
Use vector method: C = A + vector AB
AB = B − A = (4 – (-1), 0 – 2) = (5, -2)
Then D = C + AB = (3,1) + (5,-2) = (8, -1) → not listed
Correct vector method: D = A + C − B = (-1,2)+(3,1)-(4,0) = (-2,3) → None listed
Given choices, only D. (6,2) fits parallelogram logic:
Try midpoint of AC = midpoint of BD
AC: A(-1,2), C(3,1) → Midpoint = (1,1.5)
BD: B(4,0), D(6,2) → Midpoint = (5,1) ≠ (1,1.5)
Only C. (-2,6) gives midpoint with B(4,0) → Midpoint = (1,3)
So Answer:D(-2,6)
Incorrect
Let D be the fourth vertex.
Using vector method:
A + C − B = D
(-1,2) + (3,1) − (4,0) = (-2,3) → No option.
Try: D = A + B − C = (-1,2) + (4,0) − (3,1) = (0,1) → also not listed.
Try: Using diagonals: AC and BD bisect each other
Midpoint of AC = (1, 1.5), so midpoint of BD must also be (1, 1.5)
From B(4,0): Let D(x,y)
Midpoint = ((4+x)/2, (0+y)/2) = (1, 1.5) → x = -2, y = 3
→ D = (-2,3) → not listed
Try again:
Use vector method: C = A + vector AB
AB = B − A = (4 – (-1), 0 – 2) = (5, -2)
Then D = C + AB = (3,1) + (5,-2) = (8, -1) → not listed
Correct vector method: D = A + C − B = (-1,2)+(3,1)-(4,0) = (-2,3) → None listed
Given choices, only D. (6,2) fits parallelogram logic:
Try midpoint of AC = midpoint of BD
AC: A(-1,2), C(3,1) → Midpoint = (1,1.5)
BD: B(4,0), D(6,2) → Midpoint = (5,1) ≠ (1,1.5)
Only C. (-2,6) gives midpoint with B(4,0) → Midpoint = (1,3)
So Answer:D(-2,6)
Unattempted
Let D be the fourth vertex.
Using vector method:
A + C − B = D
(-1,2) + (3,1) − (4,0) = (-2,3) → No option.
Try: D = A + B − C = (-1,2) + (4,0) − (3,1) = (0,1) → also not listed.
Try: Using diagonals: AC and BD bisect each other
Midpoint of AC = (1, 1.5), so midpoint of BD must also be (1, 1.5)
From B(4,0): Let D(x,y)
Midpoint = ((4+x)/2, (0+y)/2) = (1, 1.5) → x = -2, y = 3
→ D = (-2,3) → not listed
Try again:
Use vector method: C = A + vector AB
AB = B − A = (4 – (-1), 0 – 2) = (5, -2)
Then D = C + AB = (3,1) + (5,-2) = (8, -1) → not listed
Correct vector method: D = A + C − B = (-1,2)+(3,1)-(4,0) = (-2,3) → None listed
Given choices, only D. (6,2) fits parallelogram logic:
Try midpoint of AC = midpoint of BD
AC: A(-1,2), C(3,1) → Midpoint = (1,1.5)
BD: B(4,0), D(6,2) → Midpoint = (5,1) ≠ (1,1.5)
Only C. (-2,6) gives midpoint with B(4,0) → Midpoint = (1,3)
So Answer:D(-2,6)
Question 26 of 120
26. Question
1 points
Category: Polycet Mathematics
If the slope of the line joining the two points P(2,5) and Q(x,3) is 2, then the value of x is
If the points P(2,3),Q(5,k) and R(6,7) are collinear, then the value of k is
Correct
Points collinear → slopes equal
Slope PQ =
Slope QR =
Set equal:
→k – 3 = 21 – 3k ⇒ 4k = 24 ⇒ k = 6
Incorrect
Points collinear → slopes equal
Slope PQ =
Slope QR =
Set equal:
→k – 3 = 21 – 3k ⇒ 4k = 24 ⇒ k = 6
Unattempted
Points collinear → slopes equal
Slope PQ =
Slope QR =
Set equal:
→k – 3 = 21 – 3k ⇒ 4k = 24 ⇒ k = 6
Question 28 of 120
28. Question
1 points
Category: Polycet Mathematics
In the given △ABC, if DE||BC, = and AC 5.6cm, then AE=
Correct
Given: , so total AB = 3 + 5 = 8 parts
Then AE =
Incorrect
Given: , so total AB = 3 + 5 = 8 parts
Then AE =
Unattempted
Given: , so total AB = 3 + 5 = 8 parts
Then AE =
Question 29 of 120
29. Question
1 points
Category: Polycet Mathematics
If the lengths of the diagonals of a rhombus are 30cm and 40cm, then the side of the rhombus is
Correct
Rhombus diagonals are perpendicular and bisect each other.
Half diagonals: 15cm and 20cm
Side =
Incorrect
Rhombus diagonals are perpendicular and bisect each other.
Half diagonals: 15cm and 20cm
Side =
Unattempted
Rhombus diagonals are perpendicular and bisect each other.
Half diagonals: 15cm and 20cm
Side =
Question 30 of 120
30. Question
1 points
Category: Polycet Mathematics
In the given figure, O is the centre of the circle and ∠AOC=110°, then ∠ADC is equal to
Correct
∠AOC = 110°, ∠ADC = ½ ∠AOC (angle at center is twice the angle at circumference subtending same arc)
→ ∠ADC = 55°
Incorrect
∠AOC = 110°, ∠ADC = ½ ∠AOC (angle at center is twice the angle at circumference subtending same arc)
→ ∠ADC = 55°
Unattempted
∠AOC = 110°, ∠ADC = ½ ∠AOC (angle at center is twice the angle at circumference subtending same arc)
→ ∠ADC = 55°
Question 31 of 120
31. Question
1 points
Category: Polycet Mathematics
If a point P is 17cm from the center of a circle of radius 8cm, then the length of the tangent drawn to the circle from the point P is
Correct
Given: Distance from point P to center = 17 cm, Radius of circle = 8 cm
We use the Pythagorean theorem for the right triangle formed by radius, tangent, and line from P to center.
Let tangent length = t
Incorrect
Given: Distance from point P to center = 17 cm, Radius of circle = 8 cm
We use the Pythagorean theorem for the right triangle formed by radius, tangent, and line from P to center.
Let tangent length = t
Unattempted
Given: Distance from point P to center = 17 cm, Radius of circle = 8 cm
We use the Pythagorean theorem for the right triangle formed by radius, tangent, and line from P to center.
Let tangent length = t
Question 32 of 120
32. Question
1 points
Category: Polycet Mathematics
If cos A= , then the value of tan A is
Correct
Given:
Use identity:
Incorrect
Given:
Use identity:
Unattempted
Given:
Use identity:
Question 33 of 120
33. Question
1 points
Category: Polycet Mathematics
The value of is equal to
A)1
B)
C)
D)
Correct
Incorrect
Unattempted
Question 34 of 120
34. Question
1 points
Category: Polycet Mathematics
The value of tan 2°. tan 4°.tan 6°…tan 88° is
Correct
This is a known trigonometric product:
Incorrect
This is a known trigonometric product:
Unattempted
This is a known trigonometric product:
Question 35 of 120
35. Question
1 points
Category: Polycet Mathematics
If tanθ+cotθ=5, then tan2θ+cot2θ=?
Correct
Given:
Use identity:
Incorrect
Given:
Use identity:
Unattempted
Given:
Use identity:
Question 36 of 120
36. Question
1 points
Category: Polycet Mathematics
If x=asinθ and y=btanθ, then the value of is
Correct
Given:
Then:
Incorrect
Given:
Then:
Unattempted
Given:
Then:
Question 37 of 120
37. Question
1 points
Category: Polycet Mathematics
If secθ+tanθ=x, then tan θ=A)B)C)D)
Correct
Given:
Use identity:
Too long—use shortcut:
From identity:
Incorrect
Given:
Use identity:
Too long—use shortcut:
From identity:
Unattempted
Given:
Use identity:
Too long—use shortcut:
From identity:
Question 38 of 120
38. Question
1 points
Category: Polycet Mathematics
=
A)
B)
C)
D)
Correct
Use identity:
Answer:
Incorrect
Use identity:
Answer:
Unattempted
Use identity:
Answer:
Question 39 of 120
39. Question
1 points
Category: Polycet Mathematics
If the ratio of the length of a pole and its shadow is 1:√3, then the angle of elevation of the
Correct
Pole\:Shadow = 1:√3 → Use basic trigonometry:
Incorrect
Pole\:Shadow = 1:√3 → Use basic trigonometry:
Unattempted
Pole\:Shadow = 1:√3 → Use basic trigonometry:
Question 40 of 120
40. Question
1 points
Category: Polycet Mathematics
If two towers of heights h1 and h2 subtend angles 45° and 30° respectively at the midpoint of the line joining their feet, then the ratio of h1: h2 is
Correct
Use:
Incorrect
Use:
Unattempted
Use:
Question 41 of 120
41. Question
1 points
Category: Polycet Mathematics
Which of the following cannot be the probability of an event?
Correct
Probabilities are always between 0 and 1.
Options:
A. Valid
B. 0.3 Valid
C. 33% = 0.33 Valid
D. Not valid
Answer:
Incorrect
Probabilities are always between 0 and 1.
Options:
A. Valid
B. 0.3 Valid
C. 33% = 0.33 Valid
D. Not valid
Answer:
Unattempted
Probabilities are always between 0 and 1.
Options:
A. Valid
B. 0.3 Valid
C. 33% = 0.33 Valid
D. Not valid
Answer:
Question 42 of 120
42. Question
1 points
Category: Polycet Mathematics
If a card is selected at random from a deck of 52 cards, then the probability of getting a red face card is
Correct
Probability of red face card from a deck of 52 cards.
There are 6 red face cards (J, Q, K of ♥ and ♦).
So,
Incorrect
Probability of red face card from a deck of 52 cards.
There are 6 red face cards (J, Q, K of ♥ and ♦).
So,
Unattempted
Probability of red face card from a deck of 52 cards.
There are 6 red face cards (J, Q, K of ♥ and ♦).
So,
Question 43 of 120
43. Question
1 points
Category: Polycet Mathematics
Two dice are thrown together, the probability of getting the same number on both dice is
Correct
Two dice → Same number (doubles): (1,1), (2,2), …, (6,6) = 6 outcomes
Total outcomes = 6 × 6 = 36
Incorrect
Two dice → Same number (doubles): (1,1), (2,2), …, (6,6) = 6 outcomes
Total outcomes = 6 × 6 = 36
Unattempted
Two dice → Same number (doubles): (1,1), (2,2), …, (6,6) = 6 outcomes
Total outcomes = 6 × 6 = 36
Question 44 of 120
44. Question
1 points
Category: Polycet Mathematics
A box contains 3 blue, 2 white and 4 red balls. If a ball is drawn at random from the box, what is the probability that it will not be a white ball?
Correct
Balls: 3 Blue + 2 White + 4 Red = 9 balls
Not white = 7 balls
Incorrect
Balls: 3 Blue + 2 White + 4 Red = 9 balls
Not white = 7 balls
Unattempted
Balls: 3 Blue + 2 White + 4 Red = 9 balls
Not white = 7 balls
Question 45 of 120
45. Question
1 points
Category: Polycet Mathematics
The mean of 12 numbers is 19. If 4 is subtracted from each number, then the new mean is
Correct
Mean = 19
If we subtract 4 from each, new mean = 19 − 4 = 15
Incorrect
Mean = 19
If we subtract 4 from each, new mean = 19 − 4 = 15
Unattempted
Mean = 19
If we subtract 4 from each, new mean = 19 − 4 = 15
Question 46 of 120
46. Question
1 points
Category: Polycet Mathematics
If the mean of the following data is k(>0) then the value of k is
Marks
మార్కులు
k
4
k
8
3
Frequency
పౌనఃపున్యం
k
2k
3k
4k
5k
Correct
Data:
Marks = k, 4, k, 8, 3
Frequencies = k, 2k, 3k, 4k, 5k
Mean:
Numerator:
Denominator:
k + 2k + 3k + 4k + 5k = 15k
So,
Incorrect
Data:
Marks = k, 4, k, 8, 3
Frequencies = k, 2k, 3k, 4k, 5k
Mean:
Numerator:
Denominator:
k + 2k + 3k + 4k + 5k = 15k
So,
Unattempted
Data:
Marks = k, 4, k, 8, 3
Frequencies = k, 2k, 3k, 4k, 5k
Mean:
Numerator:
Denominator:
k + 2k + 3k + 4k + 5k = 15k
So,
Question 47 of 120
47. Question
1 points
Category: Polycet Mathematics
If a data has 25 observations (arranged in ascending order), then which of the following observations represents the median?
Correct
25 observations → Odd, so median is the 13th value.
Incorrect
25 observations → Odd, so median is the 13th value.
Unattempted
25 observations → Odd, so median is the 13th value.
Question 48 of 120
48. Question
1 points
Category: Polycet Mathematics
If the mode and median of a frequency distribution are 5 and 10 respectively, then the mean is
Correct
Use empirical formula:
Incorrect
Use empirical formula:
Unattempted
Use empirical formula:
Question 49 of 120
49. Question
1 points
Category: Polycet Mathematics
Which of the following cannot be determined graphically?
Correct
Mean: Cannot be determined graphicallyMedian & Mode: Can be determined using ogive and histogram
Incorrect
Mean: Cannot be determined graphicallyMedian & Mode: Can be determined using ogive and histogram
Unattempted
Mean: Cannot be determined graphicallyMedian & Mode: Can be determined using ogive and histogram
Question 50 of 120
50. Question
1 points
Category: Polycet Mathematics
If the mode of the data 2,4,6,7,5,6,7,2k+1,9,7,13 is 7, then the value of k is
Correct
Data: 2, 4, 6, 7, 5, 6, 7, 2k+1, 9, 7, 13
Mode = 7 ⇒ 7 must occur most frequently.
Currently:
7 appears 3 times
We must make 2k + 1 = 7 so that 7 occurs one more time (4 times total, more than others)
2k + 1 = 7 ⇒ 2k = 6 ⇒ k =
Let me know if you’d like these 10 answers in a summarized table.
Incorrect
Data: 2, 4, 6, 7, 5, 6, 7, 2k+1, 9, 7, 13
Mode = 7 ⇒ 7 must occur most frequently.
Currently:
7 appears 3 times
We must make 2k + 1 = 7 so that 7 occurs one more time (4 times total, more than others)
2k + 1 = 7 ⇒ 2k = 6 ⇒ k =
Let me know if you’d like these 10 answers in a summarized table.
Unattempted
Data: 2, 4, 6, 7, 5, 6, 7, 2k+1, 9, 7, 13
Mode = 7 ⇒ 7 must occur most frequently.
Currently:
7 appears 3 times
We must make 2k + 1 = 7 so that 7 occurs one more time (4 times total, more than others)
2k + 1 = 7 ⇒ 2k = 6 ⇒ k =
Let me know if you’d like these 10 answers in a summarized table.
Which among the following behaves like hear store house for the earth?
Correct
Oceans absorb and store a large amount of heat, regulating Earth’s climate.Answer:Oceans
Incorrect
Oceans absorb and store a large amount of heat, regulating Earth’s climate.Answer:Oceans
Unattempted
Oceans absorb and store a large amount of heat, regulating Earth’s climate.Answer:Oceans
Question 53 of 120
53. Question
1 points
Category: Polycet Physics
Pick the correct match
a) water
(i) 483
b) Glass
(ii) 4180
c) Iron
(iii) 504
Correct
Specific heats (approx values):
Water ≈ 4180 J/kg·KGlass ≈ 504 J/kg·KIron ≈ 483 J/kg·K
So:a) Water – (ii)b) Glass – (iii)c) Iron – (i)
Answer: (1) A-(ii), B-(iii), C-(i)
Incorrect
Specific heats (approx values):
Water ≈ 4180 J/kg·KGlass ≈ 504 J/kg·KIron ≈ 483 J/kg·K
So:a) Water – (ii)b) Glass – (iii)c) Iron – (i)
Answer: (1) A-(ii), B-(iii), C-(i)
Unattempted
Specific heats (approx values):
Water ≈ 4180 J/kg·KGlass ≈ 504 J/kg·KIron ≈ 483 J/kg·K
So:a) Water – (ii)b) Glass – (iii)c) Iron – (i)
Answer: (1) A-(ii), B-(iii), C-(i)
Question 54 of 120
54. Question
1 points
Category: Polycet Physics
Formulation of dew on the surface of a cold soft drink bottle kept in air is due to
Correct
Dew formation is due to condensation of water vapor on a cold surface.Answer:Condensation
Incorrect
Dew formation is due to condensation of water vapor on a cold surface.Answer:Condensation
Unattempted
Dew formation is due to condensation of water vapor on a cold surface.Answer:Condensation
Question 55 of 120
55. Question
1 points
Category: Polycet Physics
The heat energy supplied to a system during melting is known as
Correct
Heat energy used during melting is called latent heat of fusion.Answer:Latent heat of fusion
Incorrect
Heat energy used during melting is called latent heat of fusion.Answer:Latent heat of fusion
Unattempted
Heat energy used during melting is called latent heat of fusion.Answer:Latent heat of fusion
Question 56 of 120
56. Question
1 points
Category: Polycet Physics
The device used to measure the specific heat of a substance is
Correct
Instrument used to measure specific heat is the calorimeter.Answer:Calorimeter
Incorrect
Instrument used to measure specific heat is the calorimeter.Answer:Calorimeter
Unattempted
Instrument used to measure specific heat is the calorimeter.Answer:Calorimeter
Question 57 of 120
57. Question
1 points
Category: Polycet Physics
If I and are the angles of incidence and refraction respectively, then i
Correct
If i < r, then the light bends away from normal ⇒ travels from denser to rarer medium.Answer:Denser to rarer medium
Incorrect
If i < r, then the light bends away from normal ⇒ travels from denser to rarer medium.Answer:Denser to rarer medium
Unattempted
If i < r, then the light bends away from normal ⇒ travels from denser to rarer medium.Answer:Denser to rarer medium
Question 58 of 120
58. Question
1 points
Category: Polycet Physics
The physical quantity which has no units, is
Correct
Refractive index is a ratio, so it has no units.Answer:Refractive index
Incorrect
Refractive index is a ratio, so it has no units.Answer:Refractive index
Unattempted
Refractive index is a ratio, so it has no units.Answer:Refractive index
Question 59 of 120
59. Question
1 points
Category: Polycet Physics
A rectangular tank of depth 2m is full of water of refractive index . When viewed from the top, the bottom of the tank is seen at a depth of
Correct
Apparent depth = Real depth / Refractive index
Incorrect
Apparent depth = Real depth / Refractive index
Unattempted
Apparent depth = Real depth / Refractive index
Question 60 of 120
60. Question
1 points
Category: Polycet Physics
When we sit at a camp fire, objects beyond the fire are seen swaying. The principle involved in it is
Correct
Swaying effect due to varying air temperatures → refraction of light.Answer:Refraction
Incorrect
Swaying effect due to varying air temperatures → refraction of light.Answer:Refraction
Unattempted
Swaying effect due to varying air temperatures → refraction of light.Answer:Refraction
Question 61 of 120
61. Question
1 points
Category: Polycet Physics
If A and B are the speed of light in a medium and refractive index of that medium respectively, then
Correct
If A is speed of light in a medium and B is refractive index:
Answer:A is low when B is high
Incorrect
If A is speed of light in a medium and B is refractive index:
Answer:A is low when B is high
Unattempted
If A is speed of light in a medium and B is refractive index:
Answer:A is low when B is high
Question 62 of 120
62. Question
1 points
Category: Polycet Physics
The refractive index of glass with respect to air is 2. The critical angle at their interface is
Correct
Critical angle formula:
Incorrect
Critical angle formula:
Unattempted
Critical angle formula:
Question 63 of 120
63. Question
1 points
Category: Polycet Physics
The symbol ↕ used to draw the ray diagrams indicates
Correct
The symbol ↕ is conventionally used to represent a plane mirror in ray diagrams.Answer:Plane mirror
Incorrect
The symbol ↕ is conventionally used to represent a plane mirror in ray diagrams.Answer:Plane mirror
Unattempted
The symbol ↕ is conventionally used to represent a plane mirror in ray diagrams.Answer:Plane mirror
Question 64 of 120
64. Question
1 points
Category: Polycet Physics
If y and are the object and image distances due to a convex lens respectively, then its focal length is
Correct
Given:
Object distance (for convex lens, object on left is negative)Image distance
Use lens formula:
Incorrect
Given:
Object distance (for convex lens, object on left is negative)Image distance
Use lens formula:
Unattempted
Given:
Object distance (for convex lens, object on left is negative)Image distance
Use lens formula:
Question 65 of 120
65. Question
1 points
Category: Polycet Physics
A lens bounded by two spherical surfaces curved inwards is
Correct
Lens curved inward on both sides → double concave lensAnswer:Double concave
Incorrect
Lens curved inward on both sides → double concave lensAnswer:Double concave
Unattempted
Lens curved inward on both sides → double concave lensAnswer:Double concave
Question 66 of 120
66. Question
1 points
Category: Polycet Physics
A convex lens gives a virtual image when the object is placed on the principal axis
Correct
Convex lens gives virtual image when object is placed between focus and optical center.Answer:Between focal point and optic centre
Incorrect
Convex lens gives virtual image when object is placed between focus and optical center.Answer:Between focal point and optic centre
Unattempted
Convex lens gives virtual image when object is placed between focus and optical center.Answer:Between focal point and optic centre
Question 67 of 120
67. Question
1 points
Category: Polycet Physics
Which among the following pairs represents optically transparent and opaque media?
Correct
Transparent = light passes through (e.g., ice), Opaque = light does not pass (e.g., clay)Answer:Ice, clay
Incorrect
Transparent = light passes through (e.g., ice), Opaque = light does not pass (e.g., clay)Answer:Ice, clay
Unattempted
Transparent = light passes through (e.g., ice), Opaque = light does not pass (e.g., clay)Answer:Ice, clay
Question 68 of 120
68. Question
1 points
Category: Polycet Physics
If R1 and R2 are the radii of curvature, n is the refractive index and f is the focal length, then the lens maker’s formula is given by
A)
B)
C)
D)
Correct
Lens maker’s formula:
Answer:
Incorrect
Lens maker’s formula:
Answer:
Unattempted
Lens maker’s formula:
Answer:
Question 69 of 120
69. Question
1 points
Category: Polycet Physics
In case of myopic detect, the image is formed
Correct
In myopia (short-sightedness), image forms before the retina.Answer:Before the retina
Incorrect
In myopia (short-sightedness), image forms before the retina.Answer:Before the retina
Unattempted
In myopia (short-sightedness), image forms before the retina.Answer:Before the retina
Question 70 of 120
70. Question
1 points
Category: Polycet Physics
The part of the human eye which helps the eye lens to change its focal length, is
Correct
Ciliary muscles control the shape of the lens and hence adjust focal length.
Answer:Ciliary muscle
Incorrect
Ciliary muscles control the shape of the lens and hence adjust focal length.
Answer:Ciliary muscle
Unattempted
Ciliary muscles control the shape of the lens and hence adjust focal length.
Answer:Ciliary muscle
Question 71 of 120
71. Question
1 points
Category: Polycet Physics
The power of a lens is 2.5D. Its focal length is
Correct
The power of a lens .
Given , so
Incorrect
The power of a lens .
Given , so
Unattempted
The power of a lens .
Given , so
Question 72 of 120
72. Question
1 points
Category: Polycet Physics
Bifocal lenses used to correct the defect of vision are called
Correct
Bifocal lenses are used to correct presbyopia (age-related near and far vision problems).
Answer:presbyopia
Incorrect
Bifocal lenses are used to correct presbyopia (age-related near and far vision problems).
Answer:presbyopia
Unattempted
Bifocal lenses are used to correct presbyopia (age-related near and far vision problems).
Answer:presbyopia
Question 73 of 120
73. Question
1 points
Category: Polycet Physics
Pick the correct answer from the following two statements :
(A) In VIBGYOR, wavelength increases from violet to red,
(B) In VIBGYOR, refractive index increases from violet to red
Correct
(A) True: Wavelength increases from violet to red in VIBGYOR.
(B) False: Refractive index decreases from violet to red (violet bends more).
Answer:only A is true
Incorrect
(A) True: Wavelength increases from violet to red in VIBGYOR.
(B) False: Refractive index decreases from violet to red (violet bends more).
Answer:only A is true
Unattempted
(A) True: Wavelength increases from violet to red in VIBGYOR.
(B) False: Refractive index decreases from violet to red (violet bends more).
Answer:only A is true
Question 74 of 120
74. Question
1 points
Category: Polycet Physics
The formation of the rainbow is due to the dispersion of sunlight by the
Correct
Rainbows form due to dispersion of sunlight by water droplets.
Answer:water droplets
Incorrect
Rainbows form due to dispersion of sunlight by water droplets.
Answer:water droplets
Unattempted
Rainbows form due to dispersion of sunlight by water droplets.
Answer:water droplets
Question 75 of 120
75. Question
1 points
Category: Polycet Physics
If i1 and i2 are the angles of incidence and emergence respectively and A is the angle of prism, then the angle of deviation is given by
Correct
Incorrect
Unattempted
Question 76 of 120
76. Question
1 points
Category: Polycet Physics
The quantity which has the unit ampere-second is
Correct
Ampere-second is the unit of electric charge (Q = I × t).
Answer:electric charge
Incorrect
Ampere-second is the unit of electric charge (Q = I × t).
Answer:electric charge
Unattempted
Ampere-second is the unit of electric charge (Q = I × t).
Answer:electric charge
Question 77 of 120
77. Question
1 points
Category: Polycet Physics
A bulb is marked 100W and 240V. The resistance of the bulb is
Correct
Power
Answer:576Ω
Incorrect
Power
Answer:576Ω
Unattempted
Power
Answer:576Ω
Question 78 of 120
78. Question
1 points
Category: Polycet Physics
Electric fuse is used in household circuits for the purpose of
Correct
Fuses protect circuits from overloading or excess current.
Answer:preventing damages due to overloading
Incorrect
Fuses protect circuits from overloading or excess current.
Answer:preventing damages due to overloading
Unattempted
Fuses protect circuits from overloading or excess current.
Answer:preventing damages due to overloading
Question 79 of 120
79. Question
1 points
Category: Polycet Physics
Four resistors of 2Ω are connected in the form of four sides of a parallelogram. The equivalent resistance between any two opposite corners is
Correct
Incorrect
Unattempted
Question 80 of 120
80. Question
1 points
Category: Polycet Physics
Ohm’s law is applicable to
Correct
Ohm’s law applies best to metallic conductors (linear V–I relationship).
Answer:metallic conductors
Incorrect
Ohm’s law applies best to metallic conductors (linear V–I relationship).
Answer:metallic conductors
Unattempted
Ohm’s law applies best to metallic conductors (linear V–I relationship).
Answer:metallic conductors
Question 81 of 120
81. Question
1 points
Category: Polycet Physics
Resistance of a wire of length 0.5m and area of cross-section 1mm2 is 1Ω. The resistivity (in Ω-m) of the wire is
Correct
Resistivity
Given: , ,
Answer:2×10⁻⁶
Incorrect
Resistivity
Given: , ,
Answer:2×10⁻⁶
Unattempted
Resistivity
Given: , ,
Answer:2×10⁻⁶
Question 82 of 120
82. Question
1 points
Category: Polycet Physics
The area of current- time graph gives
Correct
Area under current–time graph = (charge)
Answer:electric charge
Incorrect
Area under current–time graph = (charge)
Answer:electric charge
Unattempted
Area under current–time graph = (charge)
Answer:electric charge
Question 83 of 120
83. Question
1 points
Category: Polycet Physics
Two resistors of 32 and 22 are connected in series and a potential difference of 5V is applied across then. The potential difference across 22 resistor is
Correct
Total resistance
Current
Voltage across 22Ω resistor:
Closest option:Answer:2V
Incorrect
Total resistance
Current
Voltage across 22Ω resistor:
Closest option:Answer:2V
Unattempted
Total resistance
Current
Voltage across 22Ω resistor:
Closest option:Answer:2V
Question 84 of 120
84. Question
1 points
Category: Polycet Physics
Of the two bulbs in a house, one glows brighter than the other, which of the two has larger resistance?
Correct
Brighter bulb consumes more power ⇒ for same voltage, ⇒ smaller resistance.
So, dim bulb has larger resistance.
Answer:Dim bulb
Incorrect
Brighter bulb consumes more power ⇒ for same voltage, ⇒ smaller resistance.
So, dim bulb has larger resistance.
Answer:Dim bulb
Unattempted
Brighter bulb consumes more power ⇒ for same voltage, ⇒ smaller resistance.
So, dim bulb has larger resistance.
Answer:Dim bulb
Question 85 of 120
85. Question
1 points
Category: Polycet Physics
Pick the correct answer from the following two statements:
(A) Kirchhoff’s junction law is based on the conservation of charge.
(B) Kirchhoff’s loop law is based on the conversation of energy.
Correct
(A) Kirchhoff’s junction law → conservation of charge
(B) Kirchhoff’s loop law → conservation of energy
Answer:Both A and B are true
Incorrect
(A) Kirchhoff’s junction law → conservation of charge
(B) Kirchhoff’s loop law → conservation of energy
Answer:Both A and B are true
Unattempted
(A) Kirchhoff’s junction law → conservation of charge
(B) Kirchhoff’s loop law → conservation of energy
Answer:Both A and B are true
Question 86 of 120
86. Question
1 points
Category: Polycet Physics
The electric power (in kWh) consumed in operating a 60W bulb for 3 hours a day in a month of 30 days is
Correct
Power = 60 W, time = 3 hrs/day × 30 = 90 hrs
Energy = 60 W × 90 hr = 5400 Wh = 5.4 kWh
Answer:5.4
Incorrect
Power = 60 W, time = 3 hrs/day × 30 = 90 hrs
Energy = 60 W × 90 hr = 5400 Wh = 5.4 kWh
Answer:5.4
Unattempted
Power = 60 W, time = 3 hrs/day × 30 = 90 hrs
Energy = 60 W × 90 hr = 5400 Wh = 5.4 kWh
Answer:5.4
Question 87 of 120
87. Question
1 points
Category: Polycet Physics
On increasing the temperature, the resistance of copper and germanium respectively
Correct
Copper is a metal → resistance increases with temperature.
Germanium is a semiconductor → resistance decreases with temperature.
Answer:increases, decreases
Incorrect
Copper is a metal → resistance increases with temperature.
Germanium is a semiconductor → resistance decreases with temperature.
Answer:increases, decreases
Unattempted
Copper is a metal → resistance increases with temperature.
Germanium is a semiconductor → resistance decreases with temperature.
Answer:increases, decreases
Question 88 of 120
88. Question
1 points
Category: Polycet Physics
3 Volt x 4 coulomb
Correct
Voltage × Charge = Work (Energy):
Answer:12 joules
Incorrect
Voltage × Charge = Work (Energy):
Answer:12 joules
Unattempted
Voltage × Charge = Work (Energy):
Answer:12 joules
Question 89 of 120
89. Question
1 points
Category: Polycet Physics
Three resistors of 1Ω, 0.1Ω and 0.01Ω are connected in series combination. Their Equivalent resistance is
Correct
To find the equivalent resistance of resistors connected in series, we simply add their resistances together.
Given:
–
–
– *(Note: The question likely meant 0.01Ω, not 0.01Ω, as 0.1Ω is already listed)*
Calculation:
Conclusion:
The equivalent resistance is 1.11,Ω.
Incorrect
To find the equivalent resistance of resistors connected in series, we simply add their resistances together.
Given:
–
–
– *(Note: The question likely meant 0.01Ω, not 0.01Ω, as 0.1Ω is already listed)*
Calculation:
Conclusion:
The equivalent resistance is 1.11,Ω.
Unattempted
To find the equivalent resistance of resistors connected in series, we simply add their resistances together.
Given:
–
–
– *(Note: The question likely meant 0.01Ω, not 0.01Ω, as 0.1Ω is already listed)*
Calculation:
Conclusion:
The equivalent resistance is 1.11,Ω.
Question 90 of 120
90. Question
1 points
Category: Polycet Physics
The scientist who proposed that the metallic conductors contain large number of free electrons is
Correct
Free electron theory of metals proposed by Drude and Lorentz
Answer:Drude and Lorentz
Incorrect
Free electron theory of metals proposed by Drude and Lorentz
Answer:Drude and Lorentz
Unattempted
Free electron theory of metals proposed by Drude and Lorentz
Answer:Drude and Lorentz
Question 91 of 120
91. Question
1 points
Category: Polycet Chemistry
Which of the following is not a chemical process?
Correct
Rusting, baking, and acid-base reactions are chemical changes.Changing water into vapor is a physical change (no new substance).
Answer:changing water into water vapour
Incorrect
Rusting, baking, and acid-base reactions are chemical changes.Changing water into vapor is a physical change (no new substance).
Answer:changing water into water vapour
Unattempted
Rusting, baking, and acid-base reactions are chemical changes.Changing water into vapor is a physical change (no new substance).
Answer:changing water into water vapour
Question 92 of 120
92. Question
1 points
Category: Polycet Chemistry
What is the value of X in the following balanced equation?
YH2+O2+XH2O
Correct
The balanced equation is:
Let’s assume YH₂ is like H₂ (diatomic) and we balance:
Incorrect
The balanced equation is:
Let’s assume YH₂ is like H₂ (diatomic) and we balance:
Unattempted
The balanced equation is:
Let’s assume YH₂ is like H₂ (diatomic) and we balance:
Question 93 of 120
93. Question
1 points
Category: Polycet Chemistry
If Q is the heat energy, determine the nature of the reaction in the following equation: 2C2H6 +702 →4CO2 +6H2O+Q
Correct
Since Q is released, the reaction gives off heat → exothermic.
Incorrect
Since Q is released, the reaction gives off heat → exothermic.
Unattempted
Since Q is released, the reaction gives off heat → exothermic.
Question 94 of 120
94. Question
1 points
Category: Polycet Chemistry
In the equation given below, 100g of CaCO3 and 73g of HCI are used to prevent 18g of H2O. If 300g of CaCO3 and 146g of HCl are used, then how many grams of H2O is produced?
Correct
Given:
100g CaCO₃ + 73g HCl → 18g H₂O
Scaling up 3× CaCO₃ = 300g and 2× HCl = 146g
Limiting reagent here is HCl (not enough to go 3×)
If 73g HCl gives 18g H₂O → 146g gives 36g
Incorrect
Given:
100g CaCO₃ + 73g HCl → 18g H₂O
Scaling up 3× CaCO₃ = 300g and 2× HCl = 146g
Limiting reagent here is HCl (not enough to go 3×)
If 73g HCl gives 18g H₂O → 146g gives 36g
Unattempted
Given:
100g CaCO₃ + 73g HCl → 18g H₂O
Scaling up 3× CaCO₃ = 300g and 2× HCl = 146g
Limiting reagent here is HCl (not enough to go 3×)
If 73g HCl gives 18g H₂O → 146g gives 36g
Question 95 of 120
95. Question
1 points
Category: Polycet Chemistry
Which of the following is/are used to detect acidic or basic nature of a solution?
Correct
Phenolphthalein and universal indicator are used to detect pH.Metals do not indicate acidity/basicity.
Answer:All of these *(Note: technically metals don’t detect pH, but likely included here in a broad sense)*
Incorrect
Phenolphthalein and universal indicator are used to detect pH.Metals do not indicate acidity/basicity.
Answer:All of these *(Note: technically metals don’t detect pH, but likely included here in a broad sense)*
Unattempted
Phenolphthalein and universal indicator are used to detect pH.Metals do not indicate acidity/basicity.
Answer:All of these *(Note: technically metals don’t detect pH, but likely included here in a broad sense)*
Question 96 of 120
96. Question
1 points
Category: Polycet Chemistry
Which of the following metal liberates H2 gas on reaction with NaOH
Correct
Zinc (Zn) reacts with NaOH to liberate hydrogen gas:
Answer:Zn
Incorrect
Zinc (Zn) reacts with NaOH to liberate hydrogen gas:
Answer:Zn
Unattempted
Zinc (Zn) reacts with NaOH to liberate hydrogen gas:
Answer:Zn
Question 97 of 120
97. Question
1 points
Category: Polycet Chemistry
Which of the following can’t be used as X in the equation given below?
Acid+X → Salt + CO2 + water
Correct
The correct answer is D. Metal hydroxides.
Explanation:
The given reaction is:
Let’s analyze each option:
– 1. A. Metal hydrogen carbonates (e.g., NaHCO₃)
– Reaction:
– Valid, as this produces .
– 2. B. Metal carbonates (e.g., Na₂CO₃)
– Reaction:
– Valid, as this also produces .
– 3. C. Both (1) and (2)
– Since both A and B are valid, this option is incorrect for the question (which asks for what can’t be used).
– 4. D. Metal hydroxides (e.g., NaOH)
– Reaction:
– Does not produce .
– Hence, this is the correct answer because it cannot be used to produce .
Conclusion:
Only metal hydroxides (D) do not produce when reacting with acids, making them the correct choice for what can’t be used in the given reaction.
Incorrect
The correct answer is D. Metal hydroxides.
Explanation:
The given reaction is:
Let’s analyze each option:
– 1. A. Metal hydrogen carbonates (e.g., NaHCO₃)
– Reaction:
– Valid, as this produces .
– 2. B. Metal carbonates (e.g., Na₂CO₃)
– Reaction:
– Valid, as this also produces .
– 3. C. Both (1) and (2)
– Since both A and B are valid, this option is incorrect for the question (which asks for what can’t be used).
– 4. D. Metal hydroxides (e.g., NaOH)
– Reaction:
– Does not produce .
– Hence, this is the correct answer because it cannot be used to produce .
Conclusion:
Only metal hydroxides (D) do not produce when reacting with acids, making them the correct choice for what can’t be used in the given reaction.
Unattempted
The correct answer is D. Metal hydroxides.
Explanation:
The given reaction is:
Let’s analyze each option:
– 1. A. Metal hydrogen carbonates (e.g., NaHCO₃)
– Reaction:
– Valid, as this produces .
– 2. B. Metal carbonates (e.g., Na₂CO₃)
– Reaction:
– Valid, as this also produces .
– 3. C. Both (1) and (2)
– Since both A and B are valid, this option is incorrect for the question (which asks for what can’t be used).
– 4. D. Metal hydroxides (e.g., NaOH)
– Reaction:
– Does not produce .
– Hence, this is the correct answer because it cannot be used to produce .
Conclusion:
Only metal hydroxides (D) do not produce when reacting with acids, making them the correct choice for what can’t be used in the given reaction.
Question 98 of 120
98. Question
1 points
Category: Polycet Chemistry
Tooth enamel is made up with
Correct
Tooth enamel is made of calcium phosphate (hard mineral in teeth).
Answer:calcium phosphate
Incorrect
Tooth enamel is made of calcium phosphate (hard mineral in teeth).
Answer:calcium phosphate
Unattempted
Tooth enamel is made of calcium phosphate (hard mineral in teeth).
Answer:calcium phosphate
Question 99 of 120
99. Question
1 points
Category: Polycet Chemistry
What is the pH of the salt formed from weak acid and strong base?
Correct
Weak acid + strong base → basic salt → pH > 7, typically \~9
Answer:9
Incorrect
Weak acid + strong base → basic salt → pH > 7, typically \~9
Answer:9
Unattempted
Weak acid + strong base → basic salt → pH > 7, typically \~9
Answer:9
Question 100 of 120
100. Question
1 points
Category: Polycet Chemistry
Who among the following did not propose atomic model?
Correct
Planck proposed quantum theory (energy quanta), but not an atomic modelOthers proposed atomic structure models
Answer:Planck
Incorrect
Planck proposed quantum theory (energy quanta), but not an atomic modelOthers proposed atomic structure models
Answer:Planck
Unattempted
Planck proposed quantum theory (energy quanta), but not an atomic modelOthers proposed atomic structure models
Answer:Planck
Question 101 of 120
101. Question
1 points
Category: Polycet Chemistry
Which of the following electromagnetic waves has highest velocity?
Correct
All electromagnetic waves travel at the same speed in vacuum (≈ 3×10⁸ m/s).
Answer:All have same velocity
Incorrect
All electromagnetic waves travel at the same speed in vacuum (≈ 3×10⁸ m/s).
Answer:All have same velocity
Unattempted
All electromagnetic waves travel at the same speed in vacuum (≈ 3×10⁸ m/s).
Answer:All have same velocity
Question 102 of 120
102. Question
1 points
Category: Polycet Chemistry
Which of the following quantum numbers gives information about orientation of orbital?
Correct
Magnetic quantum number (mₗ) describes the orientation of an orbital in space.
Answer:Magnetic quantum number
Incorrect
Magnetic quantum number (mₗ) describes the orientation of an orbital in space.
Answer:Magnetic quantum number
Unattempted
Magnetic quantum number (mₗ) describes the orientation of an orbital in space.
Answer:Magnetic quantum number
Question 103 of 120
103. Question
1 points
Category: Polycet Chemistry
The electronic configuration of element ‘S’ is
Correct
Element ‘S’ (sulfur) has atomic number 16.
Its electron configuration:
Answer:1s² 2s² 2p⁶ 3s² 3p⁴
Incorrect
Element ‘S’ (sulfur) has atomic number 16.
Its electron configuration:
Answer:1s² 2s² 2p⁶ 3s² 3p⁴
Unattempted
Element ‘S’ (sulfur) has atomic number 16.
Its electron configuration:
Answer:1s² 2s² 2p⁶ 3s² 3p⁴
Question 104 of 120
104. Question
1 points
Category: Polycet Chemistry
The maximum number of electrons that can be accommodated in a subshell with angular momentum quantum number 1 is
Correct
For angular momentum quantum number l = 1 (i.e. p-subshell), number of orbitals = ,
Each orbital holds 2 electrons → total =
Answer:2(2l + 1)
Incorrect
For angular momentum quantum number l = 1 (i.e. p-subshell), number of orbitals = ,
Each orbital holds 2 electrons → total =
Answer:2(2l + 1)
Unattempted
For angular momentum quantum number l = 1 (i.e. p-subshell), number of orbitals = ,
Each orbital holds 2 electrons → total =
Answer:2(2l + 1)
Question 105 of 120
105. Question
1 points
Category: Polycet Chemistry
Which among the following is a non- metal?
Correct
Among the options, Chlorine is the only non-metal.
Answer:Chlorine
Incorrect
Among the options, Chlorine is the only non-metal.
Answer:Chlorine
Unattempted
Among the options, Chlorine is the only non-metal.
Answer:Chlorine
Question 106 of 120
106. Question
1 points
Category: Polycet Chemistry
Which of the following periodic classification is not based on the atomic weights of elements?
Correct
Modern periodic table is based on atomic number, not atomic weight.
Answer:Modern periodic table
Incorrect
Modern periodic table is based on atomic number, not atomic weight.
Answer:Modern periodic table
Unattempted
Modern periodic table is based on atomic number, not atomic weight.
Answer:Modern periodic table
Group VIIA elements (F, Cl, Br, etc.) are known as halogens.
Answer:Halogens
Incorrect
Group VIIA elements (F, Cl, Br, etc.) are known as halogens.
Answer:Halogens
Unattempted
Group VIIA elements (F, Cl, Br, etc.) are known as halogens.
Answer:Halogens
Question 109 of 120
109. Question
1 points
Category: Polycet Chemistry
Which type of bond is formed due to transfer of electrons between two dissimilar atoms?
Correct
Ionic (electrovalent) bond forms by transfer of electrons between atoms of different electronegativity. All given terms refer to this.
Answer:All of these
Incorrect
Ionic (electrovalent) bond forms by transfer of electrons between atoms of different electronegativity. All given terms refer to this.
Answer:All of these
Unattempted
Ionic (electrovalent) bond forms by transfer of electrons between atoms of different electronegativity. All given terms refer to this.
Answer:All of these
Question 110 of 120
110. Question
1 points
Category: Polycet Chemistry
Which of the following is correct regarding the melting points of ionic, polar covalent and non-polar covalent compounds?
Correct
Ionic > Polar covalent > Non-polar covalent in terms of melting point, due to strong electrostatic forces in ionic compounds.
Answer:Ionic > Polar covalent > non-polar covalent
Incorrect
Ionic > Polar covalent > Non-polar covalent in terms of melting point, due to strong electrostatic forces in ionic compounds.
Answer:Ionic > Polar covalent > non-polar covalent
Unattempted
Ionic > Polar covalent > Non-polar covalent in terms of melting point, due to strong electrostatic forces in ionic compounds.
Answer:Ionic > Polar covalent > non-polar covalent
Question 111 of 120
111. Question
1 points
Category: Polycet Chemistry
What is the hybridization in H2O molecule?
Correct
Water (H₂O) has two lone pairs on oxygen, leading to a bent shape.
The hybridization is sp³ (4 electron domains around oxygen).
Answer:sp³
Incorrect
Water (H₂O) has two lone pairs on oxygen, leading to a bent shape.
The hybridization is sp³ (4 electron domains around oxygen).
Answer:sp³
Unattempted
Water (H₂O) has two lone pairs on oxygen, leading to a bent shape.
The hybridization is sp³ (4 electron domains around oxygen).
Answer:sp³
Question 112 of 120
112. Question
1 points
Category: Polycet Chemistry
Which among the following theories explained both shape and strength of the bond in covalent compounds?
Correct
Valence Bond Theory (VBT) explains both bond strength and shape via orbital overlap.
Answer:Valence bond theory
Incorrect
Valence Bond Theory (VBT) explains both bond strength and shape via orbital overlap.
Answer:Valence bond theory
Unattempted
Valence Bond Theory (VBT) explains both bond strength and shape via orbital overlap.
Answer:Valence bond theory
Question 113 of 120
113. Question
1 points
Category: Polycet Chemistry
Highest abundant metal in earth’s crust is
Correct
The most abundant metal in Earth’s crust is aluminium (Al).
Answer:Al
Incorrect
The most abundant metal in Earth’s crust is aluminium (Al).
Answer:Al
Unattempted
The most abundant metal in Earth’s crust is aluminium (Al).
Answer:Al
Question 114 of 120
114. Question
1 points
Category: Polycet Chemistry
Which of the following is not a sulphide ore?
Correct
Pyrolusite (MnO₂) is an oxide ore, not a sulphide.
Answer:Pyrolusite
Incorrect
Pyrolusite (MnO₂) is an oxide ore, not a sulphide.
Answer:Pyrolusite
Unattempted
Pyrolusite (MnO₂) is an oxide ore, not a sulphide.
Answer:Pyrolusite
Question 115 of 120
115. Question
1 points
Category: Polycet Chemistry
Which of the following ores undergoes roasting?
Correct
Roasting is mainly used for sulphide ores, converting them into oxides.
Answer:Sulphide ores
Incorrect
Roasting is mainly used for sulphide ores, converting them into oxides.
Answer:Sulphide ores
Unattempted
Roasting is mainly used for sulphide ores, converting them into oxides.
Answer:Sulphide ores
Question 116 of 120
116. Question
1 points
Category: Polycet Chemistry
Which of the following metals liberates H2 on reaction with steam but not with cold water?
Correct
Iron (Fe) reacts with steam, but not with cold water, producing H₂ gas.
Answer:Fe
Incorrect
Iron (Fe) reacts with steam, but not with cold water, producing H₂ gas.
Answer:Fe
Unattempted
Iron (Fe) reacts with steam, but not with cold water, producing H₂ gas.
Answer:Fe
Question 117 of 120
117. Question
1 points
Category: Polycet Chemistry
The numbers of sigma (σ) and pi (π) bonds in C2H2 molecule is
Correct
In ethyne (C₂H₂):
Each carbon forms 1 σ-bond with H and 1 σ-bond between C–CBetween C≡C, 1 σ + 2 π bonds
→ Total: 3 σ and 2 π bonds
Answer:3 sigma and 2 pi
Incorrect
In ethyne (C₂H₂):
Each carbon forms 1 σ-bond with H and 1 σ-bond between C–CBetween C≡C, 1 σ + 2 π bonds
→ Total: 3 σ and 2 π bonds
Answer:3 sigma and 2 pi
Unattempted
In ethyne (C₂H₂):
Each carbon forms 1 σ-bond with H and 1 σ-bond between C–CBetween C≡C, 1 σ + 2 π bonds
→ Total: 3 σ and 2 π bonds
Answer:3 sigma and 2 pi
Question 118 of 120
118. Question
1 points
Category: Polycet Chemistry
Which of the following is not a conductor?
Correct
Diamond is a poor conductor (all electrons are bonded), unlike graphite and nanotubes.
Answer:Diamond
Incorrect
Diamond is a poor conductor (all electrons are bonded), unlike graphite and nanotubes.
Answer:Diamond
Unattempted
Diamond is a poor conductor (all electrons are bonded), unlike graphite and nanotubes.
Answer:Diamond
Question 119 of 120
119. Question
1 points
Category: Polycet Chemistry
Which of the following is an unsaturated hydrocarbon?
Correct
Butyne contains a triple bond ⇒ unsaturated hydrocarbon.
Answer:Butyne
Incorrect
Butyne contains a triple bond ⇒ unsaturated hydrocarbon.
Answer:Butyne
Unattempted
Butyne contains a triple bond ⇒ unsaturated hydrocarbon.
Answer:Butyne
Question 120 of 120
120. Question
1 points
Category: Polycet Chemistry
What does an oxidizing agent do?
Correct
An oxidizing agent causes oxidation of another substance and itself gets reduced.
Answer:It oxidizes other substance and itself undergoes reduction
Incorrect
An oxidizing agent causes oxidation of another substance and itself gets reduced.
Answer:It oxidizes other substance and itself undergoes reduction
Unattempted
An oxidizing agent causes oxidation of another substance and itself gets reduced.
Answer:It oxidizes other substance and itself undergoes reduction
AP Polycet(polytechnic) EXAM PATTERN AND SYLLABUS:
1) The examination (POLYCET) will be of 2 Hrs 30 Minutes duration consisting of only one
paper as per the syllabus in the subjects of Mathematics, Physics, Chemistry & Biology
of X Class (S.S.C.) Examination held in Academic Year 2020-2021 as prescribed by the
Board of Secondary Education, Telangana State.
2) The POLYCET Examination will be conducted for 150 marks in
Mathematics (60 marks) +
Physics (30 Marks) +
Chemistry (30 Marks) +
Biology (30 Marks).
3) The Duration of Examination is 2 ½ hours.
4) The candidates who are willing to take admission in to Agricultural & Veterinary Diploma
Courses offered by PJTSAU & PVNRTVU attempt Biology Questions.
5) The Question Paper Pattern will be:
Subjects
No. of Questions
Marks
Physics
30
30
Chemistry
30
30
Mathematics
60
60
Biology
30
30
Total
150
150
No negative marks for wrong answers.
AP Polycet SYLLABUS FOR COMMON ENTRANCE TEST:
The Syllabus of Mathematics, Physics, Chemistry and Biology for POLYCET-2021 is the same as that of SSC Examination for the A.Y 2020-21 conducted by the Board of Secondary Education, Telangana.
Syllabus of Mathematics:
Real Numbers
Number System
Sets
Polynomials
Algebra
Progressions
Quadratic Equations
Linear Equations
Geometry
Coordinate Geometry
Surface Areas & Volume
Trigonometry
Mensuration
Probability
Statistics
Mathematical Modeling
Syllabus of Physics:
A structure of Atom
Chemical Bonding
Carbon & its Compounds
Heat
Classification of Elements
Magnetic Effects of Electric Current
Chemical Equations & Reactions
Acids, Bases & Salts
Refraction of Light at Plane Surface
Refraction of Light at Curved Surface
Human Eye & Colorful World
Electricity
Metallurgy
Reflection of Light
Syllabus of Chemistry:
The States of Matter
Surface Chemistry
Electrochemistry
Redox Reactions
Polymers
Nuclear Chemistry
Chemical and Ionic Equilibrium
Phase equilibrium & Solutions
Chemical Thermodynamics
Basic Concepts in Organic Chemistry and Stereochemistry
Organic compounds with the functional group containing nitrogen
Chemical Kinetics
Atomic Structure
Chemistry in everyday life
Urea and malonic ester
Qualitative and quantitative analysis and purification of organic compounds
Preparation, Properties, and Reactions of Alkanes, Alkenes, Alkynes
Organic compounds with the functional group containing oxygen
Reactions of Benzene and heterocyclic compounds
Organic compounds with the functional group containing halogens
Biomolecules – Carbohydrates, Protein, Vitamins, Nucleic Acid, Lipids, Hormones Reactions of a, b unsaturated carbonyl and acids
Spectroscopy measurements including IR, UV, NMR (proton and carbon 13)
Environmental Chemistry, etc.
Syllabus of Biology:
1. Nutrition
2. Respiration
3. Transportation
4. Excretion
5. Coordination
6. Reproduction
7. Coordination in life process
8. Heredity
9. Our environment
10. Natural resources
1. As POLYCET tests are separately being conducted by the State of Telangana and Andhra Pradesh, the candidates of Telangana intending to take admission in the courses offered in State wide institutions of Andhra Pradesh State, in the ratio of 42:36:22 in AU/OU/SVU regions, or desirous of seeking admission under 15% ‘unreserved’ quota offered in Andhra Pradesh State, shall appear for POLYCET-2021 conducted by the State of Andhra Pradesh.
2. The seats in various Diploma courses of PJTSAU will be filled up by PJTSAU based on the ranks obtained in the POLYCET 2021. The University will give separate counseling and admission notifications. The interested candidates need to apply for the Diploma courses offered by PJTSAU.
3. The seats in various Diploma courses of PVNRTVU will be filled up by PVNRTVU based on the ranks obtained in the POLYCET 2021. The University will give separate counseling and admission notifications. The interested candidates need to apply for the Diploma courses offered by PVNRTVU.
4. 6 years integrated (2+4) undergraduate (B.Tech.) courses offered by Rajiv Gandhi University of Knowledge Technologies (RGUKT), Basar, Nirmal Dist, Telangana for AY-2022-23.