31) In the figure OB=13cm, OP⊥AB, OP=12cm then AB=
A) 100 cm
B) 50 cm
C) 75 cm
D) 10 cm
View Answer
D) 10 cm
Explanation:Given OB = 13 cm, OP ⊥ AB, OP = 12 cm. Find AB.
In right triangle OPB:
OB2 = OP2 + PB2 ⇒ 132 = 122 + PB2 ⇒ 169 = 144 + PB2 ⇒ PB = 5
Since OP ⊥ AB and lies at midpoint, AB = 2 × PB = 2 × 5 = 10 cm
32) In the △ABC; D, E and F are the mid points of the sides BC, CA and Ab. The are of △DEF: area of △ABC = ……
A) 1:4
B) 4:1
C) 1:3
D) 3:4
View Answer
A) 1:4
Explanation:D, E, F are midpoints of triangle ABC. Then triangle DEF is the midpoint triangle.
Area of triangle formed by joining midpoints is one-fourthof original triangle:
Correct Answer: 1:4
33) In the given figure ∠BAC=90°, AD⊥BC, BD=9cm and CD=16cm then AC=
A) 10 cm
B) 15 cm
C) 20 cm
D) 25 cm
View Answer
C) 20 cm
Explanation:∠BAC = 90°, AD ⊥ BC, BD = 9 cm, CD = 16 cm → AC = ?
This is a right triangle with altitude from right angle to hypotenuse:
Use Pythagorean relation:
In right triangle with perpendicular from right angle, AB² = BD × BC
Correct Answer: 20 cm
34) The base of two similar triangles are 24 cm and 18 cm. If one side of the first triangle is 8 cm then corresponding side of other triangle is
A) 8 cm
B) 6 cm
C) 4 cm
D) 2 cm
View Answer
B) 6 cm
Explanation:Similar triangles: base ratio = 24:18 = 4:3
So corresponding sides are in same ratio:
Correct Answer: 6 cm
35) If a parallelogram is cyclic, then it is a ……..
A) rectangle
B) square
C) quadrilateral
D) rhombus
View Answer
A) rectangle
Explanation:A cyclic parallelogram has all angles = 90°, because opposite angles in a cyclic quadrilateral are supplementary.
Only parallelogram with all 90° angles is a rectangle.
Correct Answer: A. Rectangle