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TS Polycet (Polytechnic) 2021 Previous Question Paper with Answers And Model Papers With Complete Analysis

TS Polycet (Polytechnic) 2021 Previous Question Paper with Answers And Model Papers With Complete Analysis
TS Polycet (Polytechnic) Previous Year Question Papers And Model Papers:
While preparing for TS Polycet (Polytechnic), candidates must also refer to the previous year question papers of the same. Scoring well in TS Polycet (Polytechnic) and understanding weaknesses and strengths in the respective sections.

TS Polycet (Polytechnic) Previous Year Question Papers can be found on this page in PDF format. Students taking the exam to get into some of the best Polytechnic colleges/institutes in the state of Andhra Pradesh may practice these papers to get a clear idea of the structure of the exam, marking scheme, important topics, etc.

TS Polycet Mock Test

TS POLYCET
Section — A
MATHEMATICS

1)The value of $\log_e\left(\sqrt e\right)$ is …….

A) $\frac12$

B) $\frac22$

C) $\frac32$

D) $\frac42$

View Answer

A) $\frac12$

Explanation:We are given:
$\log_e(\sqrt{e})$

Shortcut Method:
Recall:
$\log_e(e^x) = x$

Now, write $\sqrt{e}$

as an exponent:
$\sqrt{e} = e^{1/2}$

So:
$\log_e(\sqrt{e}) = \log_e(e^{1/2}) = \frac{1}{2}$

Correct Answer: $\frac{1}{2}$

2)Cardinal number of the set A={-2,-1,0,1,2} is

A) 5

B) 4

C) -2

D) 2

View Answer

A) 5
Explanation:To find the **cardinal numberof a set, simply **count the number of distinct elementsin it.
Set A = {−2, −1, 0, 1, 2}
Number of elements = 5
Correct Answer: A. 5
Want a shortcut trick for identifying cardinal numbers in big sets quickly?

3)The zeroes of the quadratic polynomial x²+24x+119 are

A) one positive and one negative

B) both positive

C) both negative

D) none of the above

View Answer

C) both negative
Explanation:We're given the quadratic polynomial:
$x^2 + 24x + 119$

To find the nature of its zeroes, we can factor it.
Try splitting the middle term:
We need two numbers that add up to 24and multiply to 119.
Check factors of 119:
119 = 17 × 7
And:
17 + 7 = 24
So we can write:
$x^2 + 24x + 119 = (x + 17)(x + 7)$

The zeroes are:
$x = -17,\quad x = -7$

Both are negative.
Correct Answer: both negative
Want a shortcut method to factor quadratics quickly using a table?

4)What is the degree of the polynomial $7u^6=\frac32u^4+6u^2-8$

A) 7

B) $-\frac32$

C) 6

D) -8

View Answer

C) 6
Explanation:Shortcut: The degreeof a polynomial is the highest power of the variable.
Here, the highest exponent of $u$

is:
$\boxed{6}$

5)H.C.F. of 8, 9 and 25 is.

A) 0

B) 1

C) 2

D) 3

View Answer

B) 1
Explanation:To find the HCF (Highest Common Factor)of 8, 9, and 25:
8= $2^3$

9= $3^2$

25= $5^2$

These numbers have no common prime factor.
Shortcut:
If no prime factor is common, then HCF = 1.

6) $\frac1{\sqrt2}$ is ……….

A) Natural number

B) Rational number

C) Irrational number

D) An integer

View Answer

C) Irrational number
Explanation:We are given the number:
$\frac{1}{\sqrt{2}}$

Step-by-step shortcut:
$\sqrt{2}$

is irrationalThe reciprocal of an irrational number is also irrational
(unless it simplifies to a rational, which $\frac{1}{\sqrt{2}}$

does not)
Final Answer: Irrational number

7)If 2^x = 8² then x=

A) 2

B) 4

C) 6

D) 8

View Answer

C) 6
Explanation:We are given:
$2^x = 8^2$

Shortcut method:
Rewrite $8$

as a power of 2:
$8 = 2^3 ⇒ 8^2 = (2^3)^2 = 2^6$

So,
$2^x = 2^6 ⇒ x = 6$

8)A={C,O,V,I,D,19,2020}, B={C,O,V,I,D,19,2021} then B-A=

A) (2020)

B) (2021)

C) (2020, 2021)

D) (C,O,V,I,D,19,2020, 2021)

View Answer

B) (2021)
Explanation:We are given two sets:
A = {C, O, V, I, D, 19, 2020}
B = {C, O, V, I, D, 19, 2021}
We are asked to find B − A, which means the elements that are in Bbut not in A.
Shortcut:
Compare both sets:
Common elements: C, O, V, I, D, 19Bhas 2021which Adoes not.
So:
$B - A = \{2021\}$

Final Answer: (2021)

9)Find the value of log_o.1 0.01

A) 1

B) 2

C) 3

D) 4

View Answer

B) 2
Explanation:We are asked to find:
$\log_{0.1}(0.01)$

Shortcut Method:
Write both numbers as powers of 10:
$0.1 = 10^{-1}$

$0.01 = 10^{-2}$

So the expression becomes:
$\log_{10^{-1}}(10^{-2})$

Use change of base formula:
$\log_{a}(b) = \frac{\log_{10}(b)}{\log_{10}(a)}$

$= \frac{\log_{10}(10^{-2})}{\log_{10}(10^{-1})} = \frac{-2}{-1} = 2$

10)The roots of x²+x-6=0 are

A) 2,-3

B) -2,3

C) 2,3

D) -2,-3

View Answer

A) 2,-3
Explanation:We are given the quadratic equation: $x^2 + x - 6 = 0$

Shortcut Method: Splitting the middle term
We need two numbers that multiply to -6and add to +1(coefficient of x):
Numbers: 3 and -2
So we factor:
x² + 3x – 2x – 6 = 0
x(x + 3) -2(x + 3) = 0
(x – 2)(x + 3) = 0
Roots are: x = 2, -3

Your Score: 0 / 0

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TS POLYCET Section — A MATHEMATICS

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TS POLYCET
Section — A
MATHEMATICS