NMMS Exam 2018 Previous Year Question Paper with Answers And Complete Analysis With Key For Practice Test Paper

Q). The area of a triangle is 57.24 square cm. If the two sides are 8 cm and 19 cm respectively, then the third side will be.
A) 15 cm
B) 21 cm
C) 20 cm
D) 15.5 cm

View Answer
A) 15 cm

Q). In the following figure AB is a diameter of a circle of radius 6 cm, C and D are points on the diameter, such that AC, CD and BD are equal. Semi circles are drawn with AC and BC as diameters. The area of the shaded region will be (Ï€ =: 3.14)

A) 37.68 cm2
B) 43.23 cm2
C) 36.68 cm2
D) 32.68 cm2

View Answer
A) 37.68 cm2

Q). The excet relation for area of a Rhombus ABCD will be
A) ½ (AC + BD)
B) ½ (AC x BD)
C) 4(AC + BD)
D) ½ x AB x BC

View Answer
B) ½ (AC x BD)
Explanation: Area of Rhombus ABCD = ½ (AC x BD)

Q). In a triangle ABC, the relation which is true for its sides is
A) AB + BC > AC
B) AB + BC < AC C) AB = BC = CA D) AB = BC + AC

View Answer
A) AB + BC > AC

Q). ΔABC is an isosceles with AB = A if ∠A=80 ,THEN ∠C =
A) 80
B) 100
C) 50
D) 40

View Answer
C) 50
Explanation: x° + x° + 80° = 180°
2x°=100°
x = 50°

Q). Area of shaded part is

A) 16 CM2
B) 8 CM2
C) 4 CM2
D) NONE

View Answer
B) 8 CM2
Explanation: Area of shaded part .
= Area of square – 2 Area of triangle
= 4×4 cm2 – 2 x ½ X 2 : 4cm2
= 16-8 cm2
= 8 cm2

Q). The ratio of the circumference of two circlesis3:4, then what is the ratio of their corresponding areas ?
A) 4:3
B) 9:16
C) 16:9
D) 3:4

View Answer
B) 9:16

Q). The area of trapezium is 31.5 cm2 and its parallel sides are 9 cm, 5 cm, then the distance between parallel sides is
A) 13.5 cm
B) 5.6 cm
C) 8.2 cm
D) 4.5 cm

View Answer
D) 4.5 cm
Explanation: ½ h(a + b) = 31.5
½ xh(9 + 5) = 31.5
7x h = 31.5
7= 31.5/7
h = 4.5 cm

Q). The diameter of a wheel is 35cm, then its circumference is
A) 110 cm
B) 220 cm
C) 95 cm
D) 100 cm

View Answer
A) 110 cm
Explanation: d = 35 cm
r= 35/2 cm
C = 2Ï€r
=2×22/7 x35/7
=22×5
=110cm

Q). \left[\frac53\right]^{-5}\times\left[\frac53\right]^{-11}=\left[\frac53\right]^{4X} , THEN X
A) 8
B) -8
C) 4
D) -4

View Answer
D) -4
Explanation: \left[\frac53\right]^{-5}\times\left[\frac53\right]^{-11}=\left[\frac53\right]^{4X}
-5-11=4x
-16x=4x
X=-16/4
X=-4

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