NMMS Exam 2018 Previous Year Question Paper with Answers And Complete Analysis With Key For Practice Test Paper

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NMMS Exam Online Mock Test

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

11 2 18
5 2 ?
12 5 14
A) 3
B) 6
C) 9
D) 12
E)16
View Answer
B) 6
Explanation: Find the difference of first two numbers in each row and double to get third number in that row.
11- 2 = 9×2 = 18
12- 5 = 7×2=14
Like that 5-2 = 3×2 =[6] So missing number = 6

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

7 4
2 8
6 5
3 0
4 8
3 ?
A) 2
B) 4
C) 6
D) 0
E) 7
View Answer
A) 2
Explanation: Multiply two numbers in first row in each rectangle and put that whole number in next row.
7 x 4 = 28 6 x 5 = 30 2×9 = 18 4×8 = 3(2)
So missing number = 2

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

A) 8
B) 5
C) 4
D) 3
E) 2

View Answer
D) 3
Explanation: Multiply two cross numbers is equal to form – a number with remaining numbers.
In first circle 7×8 = 56
In second circle
4 x 7 = 28
So, based on above rule in third circle
27÷9=(3)
So missing number = 3

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

A) 7
B) 8
C) 9
D) 10
E) 11

View Answer
D) 10
Explanation: Difference of numbers in first two pentagons ‘ is equal to the number in third pentagon at same location. Differences of
5-2 = 3
5-4= 1
9-7 = 2
11-6=5
1+9=10

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

A) 7
B) 8
C) 14
D) 15
E) 6

View Answer
C) 14
Explanation: Add the bottom two numbers and multiply it with top number to get the middle number in each triangle.
(5 + 3) x 3 = 8 x 3 = 24
(4 + 2)x5 = 6×5 = 30
Like – wise 1 + 2 = 3
42 + 3= 14
So missing number = 14

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

3 11 19
5 ? 23
7 17 29
A) 9
B) 13
C) 15
D) 21
E) 25
View Answer
B) 13
Explanation: Add the first and second numbers and. then add five to each number. We will get the third row number.
3+ 11 = 14 + 5=19
7 + 17 = 24 + 5 = 29
Like – wise
23-5= 18-5= 13

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

A) 74
B) 81
C) 29
D) 18
E) 46

View Answer
C) 29
Explanation: In each diagram multiply top two numbers and add their sum to get the bottom number
In first rectangle
(6 x 4) + (6 + 4) = 24 + 10 = 34
In second rectangle
(8 x 5) + (8 + 5) = 40 + 13 = 53
Similarly in last rectangle
(9 x 2) + (9 + 2) = 18 + 11 = 29
So missing number = 29

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

A) 1
B) 2
C) 8
D) 4
E) 5

View Answer
D) 4
Explanation: Multiply the same location numbers in first and third circles we get the same location
number in second circle.
3×2 = 6;
7×3 = 21
Like – wise
16 + 4 = 4
So the missing number = 4

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

11 7 5
1 2 3
120 45 ?
A) 15
B) 60
C) 40
D) 20
E) 16
View Answer
E) 16
Explanation: In each vertical row the difference of the square amounts of the first and second numbers is equal to the third number. In first vertical row
112=121
12= 1
121- 1 = 120
72 = 49
22 = 4
49 – 4 = 45
LIKE WISE
52 = 25
32 = 9
25 – 9 = 16
13 = 1
So missing number = 1

Q). In each of the following questions, a set of figures carrying ‘certain characters is given, Assuming that the characters in each set follow a similar pattern, find the missing character in each case

A) 125
B) 16
C) 9
D) 1
E) 4

View Answer
D) 1
Explanation: In each line cube of the one number is equal to the opposite number.
23 = 8
33 = 27
43 = 64
13= 1

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