AP Polycet (Polytechnic) 2022 Previous Question Paper with Answers And Model Papers With Complete Analysis

61)If A and B are the speed of light in a medium and refractive index of that medium respectively, then

A) A is low when B is high

B) A is high when B is high

C) A is independent of B

D) None of these

View Answer

A) A is low when B is high
Explanation:If A is speed of light in a medium and B is refractive index:
\text{Refractive index } (n = \frac{c}{v}) ⇒ \text{Higher } n ⇒ \text{Lower } v
Answer:A is low when B is high

62)The refractive index of glass with respect to air is 2. The critical angle at their interface is

A) 90°

B) 60°

C) 45°

D) 30°

View Answer

D) 30°
Explanation:Critical angle formula:
\sin C = \frac{1}{n}, \quad n = 2 ⇒ C = \sin^{-1}\left(\frac{1}{2}\right) = 30^\circ

63)The symbol ↕ used to draw the ray diagrams indicates

A) concave lens

B) convex lens

C) plano-concave lens

D) plane mirror

View Answer

D) plane mirror
Explanation:The symbol ↕ is conventionally used to represent a plane mirror in ray diagrams.Answer:Plane mirror

64)If y and \frac y4 are the object and image distances due to a convex lens respectively, then its focal length is

A) \frac{5y}4

B) \frac{4y}5

C) \frac y5

D) \frac{3y}4

View Answer

C) \frac y5
Explanation:Given:
Object distance u = -y (for convex lens, object on left is negative)Image distance v = \frac{y}{4}
Use lens formula:
\frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{\frac{y}{4}} - \frac{1}{-y} = \frac{4}{y} + \frac{1}{y} = \frac{5}{y} ⇒ f = \frac{y}{5}

65)A lens bounded by two spherical surfaces curved inwards is

A) double concave

B) double convex

C) plano-concave

D) plano – convex

View Answer

A) double concave
Explanation:Lens curved inward on both sides → double concave lensAnswer:Double concave

66)A convex lens gives a virtual image when the object is placed on the principal axis

A) at infinity

B) at the centre of curvature

C) beyond the centre of curvature

D) between focal point and optic centre

View Answer

D) between focal point and optic centre
Explanation:Convex lens gives virtual image when object is placed between focus and optical center.Answer:Between focal point and optic centre

67)Which among the following pairs represents optically transparent and opaque media?

A) Water, glass

B) Water, ice

C) Ice, clay

D) clay, wood

View Answer

A) Water, glass
Explanation:Transparent = light passes through (e.g., ice), Opaque = light does not pass (e.g., clay)Answer:Ice, clay

68)If R1 and R2 are the radii of curvature, n is the refractive index and f is the focal length, then the lens maker’s formula is given by

A) f=\left(n-1\right)\left(\frac1{R_1}-\frac1{R_2}\right)

B) f=\left(n-2\right)\left(\frac1{R_1}-\frac1{R_2}\right)

C) \frac1f=\left(n-2\right)\left(\frac1{R_1}-\frac1{R_2}\right)

D) \frac1f=\left(n-1\right)\left(\frac1{R_1}-\frac1{R_2}\right)

View Answer

D) \frac1f=\left(n-1\right)\left(\frac1{R_1}-\frac1{R_2}\right)
Explanation:Lens maker’s formula:
\frac{1}{f} = (n - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)
Answer:\frac{1}{f} = (n-1)\left( \frac{1}{R_1} - \frac{1}{R_2} \right)

69)In case of myopic detect, the image is formed

A) before the retina

B) after the retina

C) on the retina

D) does not from an image

View Answer

A) before the retina
Explanation:In myopia (short-sightedness), image forms before the retina.Answer:Before the retina

70)The part of the human eye which helps the eye lens to change its focal length, is

A) iris

B) ciliary muscle

C) cornea

D) aqueous humour

View Answer

B) ciliary muscle
Explanation:Ciliary muscles control the shape of the lens and hence adjust focal length.
Answer:Ciliary muscle
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