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AP Polycet (Polytechnic) 2022 Previous Question Paper with Answers And Model Papers With Complete Analysis

81)Resistance of a wire of length 0.5m and area of cross-section 1mm² is 1Ω. The resistivity (in Ω-m) of the wire is

A) 2×10^-3

B) 10^-3

C) 2×10^-6

D) 10^-6

View Answer

C) 2×10^-6
Explanation:Resistivity $\rho = R \cdot \frac{A}{L}$

Given: $R = 1\,Ω$

, $A = 1\,\text{mm}^2 = 1 × 10^{-6} \,\text{m}^2$

, $L = 0.5\,\text{m}$

$\rho = 1 \cdot \frac{1 × 10^{-6}}{0.5} = 2 × 10^{-6} \,Ω\text{-m}$

Answer:2×10⁻⁶

82)The area of current- time graph gives

A) potential difference

B) specific resistance

C) electric power

D) electric charge

View Answer

D) electric charge
Explanation:Area under current–time graph = $\int I\,dt = Q$

(charge)
Answer:electric charge

83)Two resistors of 32 and 22 are connected in series and a potential difference of 5V is applied across then. The potential difference across 22 resistor is

A) 2 V

B) 1 V

C) 5 V

D) 30 V

View Answer

A) 2 V
Explanation:Total resistance $R = 32 + 22 = 54\,Ω$

Current $I = \frac{V}{R} = \frac{5}{54} \,A$

Voltage across 22Ω resistor: $V = IR = \frac{5}{54} × 22 = \frac{110}{54} ≈ 2.04\,V$

Closest option:Answer:2V

84)Of the two bulbs in a house, one glows brighter than the other, which of the two has larger resistance?

A) Brighter bulb

B) Dim bulb

C) Both have same resistance

D) Brightness does not depends on resistance

View Answer

B) Dim bulb
Explanation:Brighter bulb consumes more power ⇒ for same voltage, $P = \frac{V^2}{R}$

⇒ smaller resistance.
So, dim bulb has larger resistance.
Answer:Dim bulb

85)Pick the correct answer from the following two statements:

A) Only A is true

B) Only B is true

C) Both A and B are true

D) Both B and A are false

View Answer

C) Both A and B are true
Explanation:
(A) Kirchhoff’s junction law → conservation of charge
(B) Kirchhoff’s loop law → conservation of energy
Answer:Both A and B are true

86)The electric power (in kWh) consumed in operating a 60W bulb for 3 hours a day in a month of 30 days is

A) 2.7

B) 5.4

C) 8

D) 36

View Answer

B) 5.4
Explanation:Power = 60 W, time = 3 hrs/day × 30 = 90 hrs
Energy = 60 W × 90 hr = 5400 Wh = 5.4 kWh
Answer:5.4

87)On increasing the temperature, the resistance of copper and germanium respectively

A) increases, decreases

B) decreases, increases

C) increases for both

D) decreases for both

View Answer

A) increases, decreases
Explanation:Copper is a metal → resistance increases with temperature.
Germanium is a semiconductor → resistance decreases with temperature.
Answer:increases, decreases

88)3 Volt x 4 coulomb

A) 12 watts

B) 12 amperes

C) 12 ohms

D) 12 joules

View Answer

D) 12 joules
Explanation:Voltage × Charge = Work (Energy):
$3\,V × 4\,C = 12\,J$

Answer:12 joules

89)Three resistors of 1Ω, 0.1Ω and 0.01Ω are connected in series combination. Their Equivalent resistance is

A) 1.11Ω

B) 1.12Ω

C) 2.01Ω

D) 2.1Ω

View Answer

A) 1.11Ω
Explanation:To find the equivalent resistance of resistors connected in series, we simply add their resistances together.
Given:
– $R_1 = 1\,Ω$

– $R_2 = 0.1\,Ω$

– $R_3 = 0.01\,Ω$

*(Note: The question likely meant 0.01Ω, not 0.01Ω, as 0.1Ω is already listed)*
Calculation:
$R_{\text{eq}} = R_1 + R_2 + R_3 = 1\,Ω + 0.1\,Ω + 0.01\,Ω$

$R_{\text{eq}} = 1.11\,Ω$

Conclusion:
The equivalent resistance is 1.11,Ω.

90)The scientist who proposed that the metallic conductors contain large number of free electrons is

A) Oersted

B) Ohm

C) Kircchhoff

D) Drude and Lorentz

View Answer

D) Drude and Lorentz
Explanation:Free electron theory of metals proposed by Drude and Lorentz
Answer:Drude and Lorentz

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