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TET Paper 1 Previous year question Paper Key with solutions 2024

Mathematics

91) The mean of first ten whole numbers is:
మొదటి పది పూర్ణాంకాల సగటు:

A) 5.25

B) 4.5

C) 5.5

D) 4.25

View Answer

B) 4.5
Explanation:The first ten whole numbers are: 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.
To find the mean (average):
Sum the numbers:
0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45
Divide by the number of terms:
There are 10 numbers, so divide the sum by 10:
Mean = $\frac{45}{10}$ = 4.5

92) The additive inverse of the expression (4m² – 8m + 3) is:
(4m² – 8m + 3) యొక్క సంకలన విలోమము:

A) 4m² + 8m – 3

B) -4m² – 8m – 3

C) 4m² – 8m – 3

D) -4m² + 8m – 3

View Answer

D) -4m² + 8m – 3
Explanation:The additive inverse of an expression is obtained by changing the signs of all the terms in the expression.
Given the expression:
4m² – 8m + 3
To find the additive inverse, we change the sign of each term:
– The additive inverse of 4m² is -4m².
– The additive inverse of -8m is +8m.
– The additive inverse of +3 is -3.
Therefore, the additive inverse of 4m² – 8m + 3 is:
-4m² + 8m – 3

93) The HCF of 32, 48 and 60 is:
32, 48 మరియు 60 ల యొక్క గ.సా.భా.:

A) 3

B) 6

C) 4

D) 8

View Answer

C) 4
Explanation:To find the HCF (Highest Common Factor) of 32, 48, and 60, we can use the prime factorization method.
Step 1: Prime Factorization of Each Number
– 32:( 32 = 2⁵ )
– 48:( 48 = 2⁴ X 3 )
– 60:( 60 = 2² X 3 X 5 )
Step 2: Identify the Common Factors
The only common prime factor among all three numbers is 2. Now, take the lowest power of 2 that appears in all three factorizations:
– In ( 32 = 2⁵ ), the power of 2 is 5.
– In ( 48 = 2⁴ ), the power of 2 is 4.
– In ( 60 = 2² ), the power of 2 is 2.
The lowest power of 2 is 2².
Step 3: Conclusion
The HCF of 32, 48, and 60 is: 4

94) If the radius of outer circle is ‘R’ and inner circle is ‘r’ then the formula for area of a circular path ‘A’ is:
బాహ్య వృత్త వ్యాసార్థం ‘R’ మరియు అంతర వృత్త వ్యాసార్థం ‘7’ అయిన, కంకణాకార స్థల వైశాల్యము ‘A’ నకు సూత్రం:

A) А = π(R² – r²)

B) А = π(R – г)(R − r)

C) А = π(R² + r²)

D) А = π(R + r) (R + r)

View Answer

A) А = π(R² – r²)

95) Pythagorean triplet in the following is:
క్రింది వానిలో పైథాగోరియన్ త్రికం:

A) (9, 40, 43)

B) (12, 33, 35)

C) (8, 15, 17)

D) (7, 25, 27)

View Answer

C) (8, 15, 17)
Explanation:A Pythagorean triplet consists of three positive integers a,b,c such that:
a² + b² = c²
Let’s check each of the given triplets:
(8, 15, 17)
Check if ( 8² + 15² = 17² ):
8² = 64,
15² = 225,
17² = 289
64 + 225 = 289,
289 = 289
So, (8, 15, 17) is a Pythagorean triplet.

96) $\sqrt{1296}$ =

A) 2 x 3²

B) 2² x 3²

C) 2² x 3

D) 2⁴ x 3²

View Answer

B) 2² x 3²
Explanation:To find $\sqrt{1296}$ , we need to determine the square root of 1296.
$\sqrt{1296} = 36$
Thus, $\sqrt{1296}$ = 36= 2² x 3²

97) When decimal 0.125 is expressed in simplest fractional form of $\frac pq$ , then the value pf (p+q) is:
దశాంశ సంఖ్య 0.125 ను సాధారణ భిన్న రూపం $\frac pq$ లో వ్యక్తీకరించినప్పుడు, (p + q) యొక్క విలువ:

A) 9

B) 12

C) 10

D) 8

View Answer

A) 9
Explanation:To express 0.125 as a fraction, follow these steps:
Step 1: Express 0.125 as a fraction
Since 0.125 is a decimal with three decimal places, we can write it as:
0.125 = $\frac{125}{1000}$

Step 2: Simplify the fraction
Now, we simplify $\frac{125}{1000}$ . To do this, find the greatest common divisor (GCD) of 125 and 1000. The GCD of 125 and 1000 is 125.

So, divide both the numerator and denominator by 125:

$\frac{125}{1000} = \frac{125 \div 125}{1000 \div 125} = \frac{1}{8}$

Thus, 0.125 as a simplified fraction is:
$\frac{1}{8}$

Step 3: Find ( p + q )
In the fraction $\frac{1}{8}$ , ( p = 1 \) and ( q = 8 ).

Therefore:

p + q = 1 + 8 = 9

Final Answer:
The value of ( p + q ) is 9.

98) The nearest number to 1140, which is divisible by 11 is:
11 చే నిశ్శేషంగా భాగించబడే, 1140 కి సమీప సంఖ్య:

A) 1141

B) 1143

C) 1144

D) 1139

View Answer

C) 1144
Explanation:To find the nearest number to 1140 that is divisible by 11, follow these steps:

Step 1: Divide 1140 by 11
First, divide 1140 by 11:

1140 ÷ 11 = 103.6363…

This gives approximately 103.6363, which means the quotient is 103 (when rounded down).

Step 2: Find the nearest multiple of 11
Now, let’s calculate the two multiples of 11 closest to 1140:

– The lower multiple: 11 X 103 = 1133
– The higher multiple: 11 X 104 = 1144

Step 3: Find the nearest number
– The difference between 1140 and 1133 is: 1140 – 1133 = 7
– The difference between 1140 and 1144 is: 1144 – 1140 = 4

Since 1144 is closer to 1140 than 1133, the nearest number to 1140 that is divisible by 11 is: 1144

99) 3⁸ ÷ 3⁵ =

A) 3

B) 18

C) 9

D) 27

View Answer

D) 27
Explanation:We can simplify the expression 3⁸ ÷ 3⁵ using the laws of exponents.

Rule: When dividing powers with the same base, subtract the exponents:

$\frac{a^m}{a^n} = a^{m-n}$

Apply the rule to the given expression:
$3^8 \div 3^5 = 3^{8-5} = 3^3$

Final answer:
$3^3 = 3 \times 3 \times 3 = 27$

Thus, $3^8 \div 3^5 = \boxed{27}$ .

100) Which of the following statements is INCORRECT relating to representation of data?
దత్తాంశం ప్రాతినిధ్యానికి సంబంధించి దిగువ పేర్కొన్న ప్రకటనల్లో సరికానిది ఏది?

A) A pictograph uses pictures or symbols to represent the frequency of the data.
పటచిత్రంలో దత్తాంశం యొక్క పౌనఃపున్యాన్ని సూచించడానికి పటాలను లేదా గుర్తులను ఉపయోగిస్తారు.

B) Bar graphs are used to represent independent observations with frequencies.
దత్తాంశంలోని విభక్త రాశులను వాటి పౌనఃపున్యంతో పోల్చవలసినప్పుడు కమ్మీరేఖా చిత్రాలు ఉపయోగిస్తారు.

C) A pie chart is used to present two observations side by side only.
వృత్త రేఖా చిత్రం (పై చార్జ్) రెండు పరిశీలనలను పక్కపక్కనే ప్రదర్శించడానికి మాత్రమే ఉపయోగించబడుతుంది.

D) Histogram is a graphical representation of frequency distribution of exclusive class intervals.
హిస్టోగ్రామ్ అనేది ప్రత్యేక తరగతి అంతరాలకు, పౌనఃపున్య విభజనకు గీయబడిన రేఖా చిత్రం.

View Answer

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Mathematics

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