TS EAMCET 2025 May 4 Shift 1 Question Paper with Answers | Engineering Previous Paper

141) Sodium metal crystallises in a body centred cubic lattice with edge length of xÅ. If the radius of sodium atom is 1.86Å, the value of x is

A) 4.29

B) 3.29

C) 2.39

D) 3.93

View Answer

A) 4.29
Explanation:BCC relation a=\frac{4r}{\sqrt{3}}
142) In a mixture of liquids A and B, if the mole fractions of component A in vapour phase and liquid mixture are x1 and x2 respectively, then the total vapour pressure of liquid mixture is (where P_A^0 and P_B^0 are the vapour pressures of pure A and B)

A) P_B^0 \frac{x_1}{x_2}

B) P_B^0 \frac{x_2}{x_1}

C) P_A^0 \frac{x_2}{x_1}

D) P_A^0 \frac{x_1}{x_2}

View Answer

C) P_A^0 \frac{x_2}{x_1}
Explanation:Raoult’s law
143) A current of 0.5 ampere is passed through molten AlCl₃ for 96.5 seconds. The mass of aluminium deposited at cathode is x mg and volume of chlorine liberated (at STP) at anode is y mL. x and y are respectively

A) 18,22.4

B) 13.5,16.8

C) 9,11.2

D) 4.5,5.6

View Answer

D) 4.5,5.6
Explanation:Faraday law
Charge passed:
Q = It = 0.5 × 96.5 = 48.25 C
Faraday = 96500 C ⇒ moles of electrons:
= 48.25 / 96500 = 1/2000 mol
Cathode:
Al³⁺ + 3e⁻ → Al
Moles of Al:
= (1/2000)/3 = 1/6000 mol
Mass:
= (27 × 1000)/6000 mg
= 27000/6000 = 4.5 mg
⇒ x = 4.5 mg
Anode:
2Cl⁻ → Cl₂ + 2e⁻
Moles of Cl₂:
= (1/2000)/2 = 1/4000 mol
Volume at STP:
= (1/4000) × 22400 mL
= 5.6 mL
⇒ y = 5.6 mL
Final Answer:
(D) 4.5, 5.6
144) R→P is a first order reaction. For this reaction a graph of ln[R] (on y-axis) and time (on x-axis) gave a straight line with negative slope. The intercept on y-axis is equal to (k=rate constant)

A) ln[R]0

B) [R]0

C) k×2.303

D) k/2.303

View Answer

A) ln[R]0
Explanation:ln[R] vs t intercept
145) The correct statements about the properties of colloidal solutions are
→A.Tyndall effect is used to distinguish between a colloidal solution and a true
solution
→B.Zeta potential is related to movement of colloidal particles
→C.Brownian motion in colloidal solution is faster if the viscosity of the solution is
very high
→D.Brownian motion stabilises the sols

A) A,B

B) B,C

C) A,D

D) B,D

View Answer

C) A,D
Explanation:Colloid properties
146) The ore of which metal is concentrated by leaching?

A) Zn

B) Cu

C) Al

D) Fe

View Answer

C) Al
Explanation:Bayer process
147) Arrange the following molecules in the correct order of their bond angles: S₈, P₄, S₆, O₃

A) A ¡ C ¡ D ¡ B

B) B ¡ A ¡ C ¡ D

C) C ¡ B ¡ A ¡ D

D) B ¡ C ¡ A ¡ D

View Answer

D) B ¡ C ¡ A ¡ D
Explanation:Structure comparison
148) What are the products formed when ammonium dichromate is thermally decomposed?

A) NO₂, Cr₂O₃, H₂

B) N₂O, Cr₂O₃, H₂O

C) N₂, CrO₃, H₂O

D) N₂, Cr₂O₃, H₂O

View Answer

D) N₂, Cr₂O₃, H₂O
Explanation:Thermal decomposition
149) Sulphur dioxide on reaction with chlorine in the presence of charcoal gives compound (A). This on reaction with white phosphorus gives SO₂ and compound (B). The correct statement about ‘B’ is

A) The shape of ‘B’ is pyramidal

B) ‘B’ on hydrolysis gives phosphorus acid

C) ‘B’ in solid state exists as an ionic solid

D) In ‘B’ all bonds are equivalent

View Answer

C) ‘B’ in solid state exists as an ionic solid
Explanation:⇒ Formation of Compound (A):
Sulphur dioxide (SO_2) reacts with chlorine (Cl_2) in the presence of charcoal (catalyst) to form Sulfuryl chloride (SO_2Cl_2).
Reaction: SO_2 + Cl_2 \xrightarrow{charcoal} SO_2Cl_2
Therefore, Compound (A) is SO_2Cl_2.
Formation of Compound (B):
White phosphorus (P_4) reacts with sulfuryl chloride to produce phosphorus pentachloride (PCl_5) and sulfur dioxide.
Reaction: P_4 + 10SO_2Cl_2 \rightarrow 4PCl_5 + 10SO_2
Therefore, Compound (B) is PCl_5.
Analysis of Statement (C):
In the solid state, PCl_5 does not exist as a simple covalent molecule. It exists as an ionic solid composed of tetrahedral [PCl_4]^+ cations and octahedral [PCl_6]^- anions.
2PCl_5 \text{ (solid)} \rightarrow [PCl_4]^+[PCl_6]^-
This makes statement (C) correct.
Evaluation of Other Options:
(A): The shape of PCl_5 in the gas phase is trigonal bipyramidal, not pyramidal.
(B): Hydrolysis of PCl_5 yields phosphoric acid (H_3PO_4), not phosphorous acid (H_3PO_3).
(D): In the trigonal bipyramidal structure of PCl_5, the two axial bonds are longer and weaker than the three equatorial bonds. Thus, not all bonds are equivalent.
150) In which of the following transition metal ion (aquated) is not correctly matched with its colour?

A) Fe²⁺- Green

B) Cu²⁺- Blue

C) Fe³⁺- Pink

D) V³⁺- Green

View Answer

C) Fe³⁺- Pink
Explanation:Fe3+ not pink
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